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3 hours ago · Since the stoichiometry is 1:1, the moles of HCl needed to neutralize the NaOH is also 3.9515 mmol. Now, we can calculate the volume of HCl needed using the formula: Volume = Moles / Molarity So, the volume of HCl = 3.9515 mmol / 0.340 M = 11.62 mL. Answer Therefore, 11.62 mL of 0.340 M HCl would be needed to titrate 14.91 mL of 0.265 M NaOH.
