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1. • • In these scenarios, we can use LINQ's ToDictionary () method. Here's an example: // Define a list of integers List list = new List () { 1, 2, 3, 4, 5 }; // Initialize a dictionary from the list, where the value is the square of the key Dictionary dict = list.ToDictionary(x => x, x => x * x);
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     Guide to Initialize a Dictionary in C# | C# Tutorial

2. Top results related to how to initialize a dictionary in c# with example function

   • Initialize a Dictionary with values in C# 2.0

     Top Answer

     Answered Jul 19, 2013 · 10 votes

     But it doesn't work in C# 2.0. Is there any workaround for this without using Add or basing on an already existing collection?

     No. The closest I can think of would be to write your own DictionaryBuilder type to make it simpler:

     public class DictionaryBuilder<TKey, TValue>{ private Dictionary<TKey, TValue> dictionary = new Dictionary<TKey, TValue> dictionary(); public DictionaryBuilder<TKey, TValue> Add(TKey key, TValue value) { if (dictionary == null) { throw new InvalidOperationException("Can't add after building"); } dictionary.Add(key, value); return this; } public Dictionary<TKey, TValue> Build() { Dictionary<TKey, TValue> ret = dictionary; dictionary = null; return ret; }}

     Then you can use:

     Dictionary<string, int> x = new DictionaryBuilder<string, int>() .Add("Foo", 10) .Add("Bar", 20) .Build();

     This is at least a single expression still, which is useful for fields where you want to initialize at the point of declaration.

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     1/5

   • In C#: How to declare a generic Dictionary with a type as key and an IEnumerable<> of that type as value?

     Top Answer

     Answered Dec 01, 2017 · 21 votes

     You may not even need a dictionary to be able to do this - but that depends on your needs. If you only ever need 1 such list per type per appdomain (i.e. the "dictionary" is static), the following pattern can be efficient and promotes type-inference nicely:

     interface IBase {}-static class Container { static class PerType<T> where T : IBase { public static IEnumerable<T> list; } public static IEnumerable<T> Get<T>() where T : IBase => PerType<T>.list; public static void Set<T>(IEnumerable<T> newlist) where T : IBase => PerType<T>.list = newlist; public static IEnumerable<T> GetByExample<T>(T ignoredExample) where T : IBase => Get<T>(); }

     Note that you should think carefully before adopting this approach about the distinction between compile-time type and run-time type. This method will happily let you store a runtime-typed IEnumerable<SomeType> variable both under SomeType and -if you cast it- under any of SomeType's base types, including IBase, with neither a runtime nor compiletype error - which might be a feature, or a bug waiting to happen, so you may want an if to check that.

     Additionally, this approach ignores threading; so if you want to access this data-structure from multiple threads, you probably want to add some locking. Reference read/writes are atomic, so you're not going to get corruption if you fail to lock, but stale data and race conditions are certainly possible.

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     2/5

   • How to pass dictionary items to a function in C#

     Top Answer

     Answered Oct 13, 2013 · 1 votes

     Could you do something like this:

     public static MvcHtmlString ActionMenuItem( this HtmlHelper htmlHelper, String linkText, String actionName, String controllerName, String iconType = null, string classCustom = null, params KeyValuePair<string, string>[] subMenus){ ... }var dict = new Dictionary<string, string>(){ { "a", "b" }, { "c", "d" },};*.ActionMenuItem(*, *, *, *, *, dict.ToArray());

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     3/5

   • How to initialize a double array with various values using switch case in C#

     Top Answer

     Answered Jul 15, 2015 · 0 votes

     You were close, you just have to use new to initialize the arrays:

     double [] test1; int value; // Which I will get it from DBSwitch (value){case 1: test1 = new double[] {1, 0, 0,1}; break;case 2: test1 = new double[] {0, 0, 0,1}; break;case 3: test1 = new double[] {0, 0, 1,1}; break;case 4: test1 = new double[] {1, 0, 1,1}; break;}

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     4/5

   • How to Draw a rectangle on image using Emgu CV libraries in C#. with an example

     Top Answer

     Answered Nov 25, 2021 · 1 votes

     Most things you know how to do in Python with OpenCV can be done in C# Emgu with CvInvoke.

     For instance, this site shows the Rectangle method for drawing a rectangle onto a given image.

     public static void Rectangle( IInputOutputArray img, Rectangle rect, MCvScalar color, int thickness = 1, LineType lineType = LineType.EightConnected, int shift = 0)

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3. People also ask

   How to initialize a dictionary?

   • To initialize a dictionary, we can enclose each set of key-value in curly braces. Internally for each pair, the compiler makes a call to Dictionary’s Add() method. This is demonstrated below: 2. Index Initializer We can also initialize a dictionary using an index initializer, as shown below.

   Initialize a Dictionary in C# | Techie Delight

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   How to initialize a dictionary in c# 6?

   • Another way to initialize a dictionary is object initializer introduced in C# 6: To add an item to a dictionary, we use the Add method. For example: This would add "Adam" and his age of 24 to the nameToAge dictionary. To remove an item from a dictionary, we use the Remove method. For example: This would remove "Adam" from the nameToAge dictionary.

   C# Dictionary: Complete Guide [2023] - Josip Miskovic

   josipmisko.com/posts/c-sharp-dictionary

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   How to initialize a dictionary with key-value pairs?

   • Besides creating an empty dictionary, we can also initialize a dictionary with some key-value pairs at the time of creation. Consider the following example: { "apple", 1 }, { "banana", 2 }, { "cherry", 3 } In this code snippet, we have created a dictionary, "dict", and initialized it with three key-value pairs.

   Guide to Initialize a Dictionary in C# | C# Tutorial

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   How to create a dictionary in C#?

   • Dictionary Builder To create a dictionary with several entries, it’s better to create a type-safe DictionaryBuilder class. Then we can use Builder’s Add() method, which takes key-value pairs instead of a dictionary. The Add() associates key with value in the built dictionary. That’s all about initializing a Dictionary in C#.

   Initialize a Dictionary in C# | Techie Delight

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4. learn.microsoft.com › en-us › dotnetHow to initialize a dictionary with a collection initializer - C#

   learn.microsoft.com › en-us › dotnet

   • Cached

   Mar 15, 2024 · Learn how to initialize a dictionary in C#, using either the Add method or an index initializer. This example shows both options. How to initialize a dictionary with a collection initializer - C# | Microsoft Learn

5. stackoverflow.com › questions › 10998961c# - Adding values to a dictionary via inline initialization ...

   stackoverflow.com › questions › 10998961

   • Cached

   Mar 10, 2017 · var numbers = new Dictionary<int, string> { [7] = "seven", [9] = "nine", [13] = "thirteen" }; The preceding sample generates code that calls the Item[TKey] to set the values. Before C# 6, you could initialize dictionaries and other associative containers using the following syntax.

   • this is actual inline intialization: private IDictionary localizedNames = new Dictionary { {"key1","value1"},...
   • AllCities.Add(new City("Rome") { Names = { { "DE", "Rom" }, { "...", "..." } } }); This is using initializer syntax to invoke the .Add method.
   • There's a better approach to this than using anonymous objects : Dictionary dict = new() { ["key1"] = "value1", ["key2"] =...

6. Videos

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7. josipmisko.com › posts › c-sharp-dictionaryC# Dictionary: Complete Guide [2023] – Josip Miskovic

   josipmisko.com › posts › c-sharp-dictionary

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   Jan 26, 2023 · Initialization. To initialize a dictionary in C#, we first need to provide the type for the key and the type for the value. For example, for a dictionary that stores the name and age of a person, the initialization would be: C# Dictionary<string, int> nameToAge = new Dictionary<string, int>();

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8. www.gyata.ai › c-sharp › c-initialize-dictionaryGuide to Initialize a Dictionary in C# | C# Tutorial

   www.gyata.ai › c-sharp › c-initialize-dictionary

   • Cached

   Dec 8, 2023 · The simplest way to initialize a dictionary in C# is to create an empty dictionary. The following code illustrates how to do this: // Define a new dictionary of string keys and integer values Dictionary dict = new Dictionary (); In the above code, we have created a dictionary, "dict", with keys of type string and values of type int.

9. www.techiedelight.com › initialize-dictionary-csharpInitialize a Dictionary in C# | Techie Delight

   www.techiedelight.com › initialize-dictionary-csharp

   • Cached

   Apr 6, 2024 · 1. Collection Initializer. To initialize a dictionary, we can enclose each set of key-value in curly braces. Internally for each pair, the compiler makes a call to Dictionary’s Add() method. This is demonstrated below: Download Run Code. 2. Index Initializer. We can also initialize a dictionary using an index initializer, as shown below.

10. makolyte.com › csharp-initialize-a-dictionaryC# - Initialize a dictionary | makolyte

    makolyte.com › csharp-initialize-a-dictionary

    • Cached

    Sep 12, 2023 · Option 1 – Initialize dictionary with values using indexer syntax. Here’s an example of initializing a dictionary with multiple key/value pairs using the indexer syntax (i.e. [key]=value): using System.Collections.Generic; var dictionary = new Dictionary< string, int >() { ["Bob"] = 1, ["Linda"] = 2, ["Teddy"] = 3}; Code language: C# (cs)

11. puzzledbycsharp.com › dictionary › how-to-initializeHow To Initialize A Dictionary In C# - puzzledbycsharp.com

    puzzledbycsharp.com › dictionary › how-to-initialize

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    See the example below. Dictionary<string, string> salaryDictionary = new Dictionary<string, string>() { ["Bob"] = "50000", ["Jil"] = "60000", ["John"] = "70000", ["Jen"] = "80000" };//Initialize the dictionary with a Index Initializer.