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  2. Suppose we have a dictionary like this: Dictionary<int, string> dict = new Dictionary<int, string>(); dict.Add(1, "Mohan"); dict.Add(2, "Kishor"); dict.Add(3, "Pankaj"); dict.Add(4, "Jeetu"); We can initialize it as follows. Dictionary<int, string> dict = new Dictionary<int, string>. {.

    Code sample

    var myDict = new Dictionary<string, string> {
      { "key1", "value1" },
      { "key2", "value2" }
    };
    Console.ReadKey();...
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    A Dictionary contains a collection of key/value pairs. Its Add method takes two parameters, one for the key and one for the value. One way to initialize a Dictionary , or any collection whose Add method takes multiple parameters, is to enclose each set of parameters in braces as shown in the following example. Another optio...

    In the following code example, a Dictionary is initialized with instances of type StudentName. The first initialization uses the Add method with two arguments. The compiler generates a call to Add for each of the pairs of int keys and StudentName values. The second uses a public read / write indexer method of the Dictionary class:

    Note the two pairs of braces in each element of the collection in the first declaration. The innermost braces enclose the object initializer for the StudentName, and the outermost braces enclose the initializer for the key/value pair that will be added to the students Dictionary . Finally, the whole collection initializer for the dictionary is enclosed in braces. In the second initialization, the left side of the assignment is the key and the right side is the value, using an object initializer for StudentName.

    •C# Programming Guide

    •Object and Collection Initializers

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  4. Initialize dictionary with value (C#) Asked 3 years, 11 months ago. Modified 3 years, 11 months ago. Viewed 2k times. 0. I have model with Dictionary, that I want to initialize with default value Here is how I do it now. public Dictionary<string, string> controllableProperties = new Dictionary<string, string> {

  5. Sep 12, 2023 · Option 1 – Initialize dictionary with values using indexer syntax. Here’s an example of initializing a dictionary with multiple key/value pairs using the indexer syntax (i.e. [key]=value): using System.Collections.Generic; var dictionary = new Dictionary< string, int >() { ["Bob"] = 1, ["Linda"] = 2, ["Teddy"] = 3}; Code language: C# (cs)

  6. Dec 8, 2023 · Table of Contents. 1. Initializing an Empty Dictionary. 2. Initializing a Dictionary with Key-Value Pairs. 3. Initializing a Dictionary from an Array, List, or Other Enumerable. 4. Tips, Tricks, and Common Pitfalls. 4.1 Duplicate Keys. 4.2 Null Keys. 4.3 Key Not Found. 5. Conclusion.

  7. Apr 6, 2024 · 1. Collection Initializer. To initialize a dictionary, we can enclose each set of key-value in curly braces. Internally for each pair, the compiler makes a call to Dictionarys Add() method. This is demonstrated below: Download Run Code. 2. Index Initializer. We can also initialize a dictionary using an index initializer, as shown below.

  8. The following example shows how to create a dictionary and add key-value pairs. Example: Create Dictionary and Add Elements IDictionary < int , string > numberNames = new Dictionary < int , string >(); numberNames.Add(1, "One" ); //adding a key/value using the Add() method numberNames.Add(2, "Two" ); numberNames.Add(3, "Three" ); //The ...

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