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public static void main(String[] args) { // year to be checked int year = 1900; boolean leap = false; // if the year is divided by 4 if (year % 4 == 0) { // if the year is century if (year % 100 == 0) { // if year is divided by 400 // then it is a leap year if (year % 400 == 0) leap = true; else . leap = false; }
- Find Factorial of a Number
Check Leap Year . Check Whether a Number is Positive or...
- Check Whether a Number is Positive Or Negative
Check Leap Year . Check Whether a Number is Positive or...
- Find Factorial of a Number
- Using Scanner Class
- Using Ternary Operator
- Using In-Built Isleap() Method
Here the user is provided the flexibility to enter the year of their own choice as Scanner Class is imported here rest of the if-else blocks are also combined in a single statement to check if the input year is a leap year. Below is the Java program to implement the approach: Input Output
Ternary Operator is used to reduce the if-else statements. The ternary operator takes three operands, a boolean condition, an expression to execute if the condition is true, and an expression to execute if false. Below is the Java program to implement the approach:
Java has an in-built isLeap() method to check if the input year is a leap year or not. Below is the Java program to implement the approach:
- 11 min
import java.util.Scanner; public class lecture{ public static void main(String[] args) { boolean loop=true; Scanner console = new Scanner( System.in ); while (loop){ System.out.print( "Enter the year: " ); int year= console.nextInt(); System.out.println( "The year is a leap year: "+ leapYear(year) ); System.out.print( "again?: " ); int again ...
Code sample
public static boolean isLeapYear(int year) {Calendar cal = Calendar.getInstance();cal.set(Calendar.YEAR, year);return cal.getActualMaximum(Calendar.DAY_OF_YEAR) > 365;}Apr 21, 2024 · A LEAP YEAR, also known as an intercalary year or a bissextile year is a calendar year containing 366 days, as compared to the regular 365 days a year. The extra day is added to balance out the drift between an astronomical year and a seasonal year. The Earth’s revolution generally takes 365.25 days approx to complete.
Jan 8, 2024 · Since Java 1.1, the GregorianCalendar class allows us to check if a year is a leap year: public boolean isLeapYear(int year); As we might expect, this method returns true if the given year is a leap year and false for non-leap years.
May 20, 2024 · Ever wondered if a specific year is a leap year? 🗓️ Learn how to determine leap years with a simple Java program! Watch this quick tutorial to see the logic...
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People also ask
How to check if a year is a leap year in Java?
How to check if input year is a leap year?
Is a leap year divisible by 4?
How to identify a leap year?
A non-century year is a leap year if the year is divisible by 4. For example, 1996 is a leap year, and 1999 is not a leap year, as the former one is divisible by 4 and the latter one is not divisible by 4.