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-x + 6 = 2. Solve for x: x = 6 - 2. x = 4. Solution: x = 4, y = 1.5. Test the solution: 3 × 4 - 4 × 1.5 = 12 - 6 = 6. We see that the first equation is OK.-4 + 4 × 1.5 = -4 + 6 = 2. And the second equation is OK as well. Solve using substitution method: 2x + 3y = 5. 2x + 7y = -3. Solve the first equation for x: x = -1.5y + 2.5. Substitute x ...
May 15, 2024 · The quadratic formula is as follows: x = (-B ± √Δ)/2A. where: Δ = B² – 4AC. Using this formula, you can find the solutions to any quadratic equation. Note that there are three possible options for obtaining a result: The quadratic equation has two unique roots when Δ > 0.
1 day ago · Struggling with (x+3)/3=(10+4)/4? Watch our step-by-step video on Tiger Algebra to master this linear equation effortlessly.
- 2 min
- Tiger Algebra
2 days ago · 3. Eight divided by a number equals four. Solutions. 1. The solution is 9 - x = 5. 2. The correct answer is m x 6 = 12. 3. The equation is written like this: 8 ÷ n = 4. Tip: Keep in mind that you can use any variable you want to write these equations. It doesn't need to be the same as the variable in the answer, but it does need to be in the ...
May 1, 2024 · 1. Solve x 6 + 5 x 3 + 6 = 0. Solution: Since we want to rewrite this equation as a quadratic equation, we use substitution by letting z = x 3. So the equation becomes: ( x 3) 2 + 5 ( x 3) + 6 = 0. ⇒ z 2 + 5 z + 6 = 0. We can now solve this quadratic equation by factoring, giving us: ( z + 2) ( z + 3) = 0. ⇒ z = − 2 or z = − 3.
- Srishta Chopra
- 2017
May 16, 2024 · From the given \[(x - 3)(x - 4) = \dfrac{{34}}{{{{33}^2}}}\] \[{33^2} = 1089\] \[{x^2} - 4x - 3x + 12 = \dfrac{{34}}{{1089}}\] \[{x^2} - 7x + 12 = \dfrac{{34}}{{1089}}\] Cross multiplying we get, \[1089{x^2} - 7623x + 13068 = 34\] \[1089{x^2} - 7623x + 13034 = 0\]
May 12, 2024 · 2 Answers. Sorted by: 2. x = (√x2 + 50x − 4 − x)2 + 2(√x2 + 50x − 4 − x)x + 4 50 Expand the square to get x = x2 + 50x − 4 + x2 − 2x2 + 4 50 x = x. This seems to be an identity. This is true when x satisfies the domain of ( √x2 + 50x − 4 − x)2 + 2 ( √x2 + 50x − 4 − x) x + 4 50. Which means x2 + 50x − 4 ≥ 0 (x + 25 + √629)(x − 25 + √629) ≤ 0.
