Search results
Overview. The scanner transport is designed for fragile original film. Film tension is electronically controlled using new proprietary technology and is adjustable over a wide range, from 6 to 30 ounces – constantly displayed on the control monitor. Percentage of film shrinkage is also displayed and constantly updated.
Mar 11, 2016 · The Kinetta, a creation developed by Jeff Kreines, was made with an archival environment in mind. The scanner can accommodate the handling of a film in healthy condition, and it can handle a film that has been beaten up and shrunken. CFA has films that fall into both of those categories and every category in between.
Our gentlest option, the Kinetta Archival Film Scanner is a sprocketless flatbed scanner capable of producing 4K edge-to-edge scans of 35mm and 16mm film, with optical sound on both of these formats. This scanner was specifically designed for damaged, shrunken, and warped film that won’t run through other systems.
The Kinetta is a film scanner, capable of scanning various film formats at various resolutions, which evolved from an earlier digital camera project. References [ edit ] NAB 2004 article (digitalcontentproducer.com)
May 5, 2021 · Addeddate 2021-05-05 17:15:10 Identifier kinetta-desktop-cine-film-scanner Identifier-ark ark:/13960/t6f29t27s Ocr tesseract 5.0.0-alpha-20201231-10-g1236
A uniquely gentle transport, curved gates, and adjustable tension allows the Kinetta to capture highly compromised film. We use it to scan replasticized films, both archival film and home movies. 8mm, Super8mm, 9.5mm, 16mm, 17.5mm, 28mm, & 35mm; Auto perf-based stabilization; 6.5K scan resolution
People also ask
What is a Kinetta archive scanner?
Do Kinetta scanners have sprockets?
Which archival film scanner is best?
Mar 28, 2024 · The Kinetta is definitely a nicer machine, more mature, and appears to be much more solidly built than what I saw of the Filmic scanner at NAB last year. They may promote it to archives, but it does not look like it can keep warped film flat. (edit- Dan Baxter answered question.)
