Yahoo Web Search

Search results

1. Top results related to java random number generator integer

   • java random number generator - lottery

     Top Answer

     Answered Apr 11, 2012 · 0 votes

     Do you mean that you expect the proportion of times that you win to be more "random"? If that's what you're getting at, then @truthreality is quite correct. For further reading you might look at the law of large numbers and the central limit theorem.

     If you're asking if your method of shuffling is correct, it is though it is inefficient. You're generating more random numbers than necessary, since you're just checking for dupes when they occur, and you're not creating a new random number after you pick a ball, so you're requiring a minimum of one HashMap.get(int) per pick.

     I might use one of the following methods instead:

     1) Create an ArrayList containing all the ball values. For each drawing, use Collections.shuffle(yourArrList, rand) to shuffle a clone of it them, then just use the first 5 balls from the list.

     2) Again, create an Array or ArrayList of ball values. Then implement a portion of the shuffle operation yourself: Choose from smaller and smaller subsets of the possibilities and swap in the element that no longer fits into the place of the element that was just chosen. The advantage is that you don't need to shuffle the entire array. Here's my quick and dirty implementation:

     public static int[] choose(int[] array, int count, Random rand) { int[] ar = array.clone(); int[] out = new int[count]; int max = ar.length; for (int i = 0; i<count; i++) { int r = rand.nextInt(max); //max is decremented, //the selected value is copied out then overwritten //by the last value, which would no longer be accessible max--; out[i]=ar[r]; ar[r]=ar[max]; } return out;}-

     There's probably room for improvement, especially if order doesn't matter.

     Check all answers on Stack Overflow

     1/5

   • Java Random Number Generator using a Seed

     Top Answer

     Answered Sep 19, 2012 · 1 votes

     That's totally normal and a feature : in a Pseudo Random Generator, the seed defines the sequence of numbers that will be generated.

     Check all answers on Stack Overflow

     2/5

   • java random number generator and their distribution

     Top Answer

     Answered Oct 06, 2016 · 2 votes

     You appear to be describing a uniform distribution.

     Looking at the Javadoc of Random.nextInt(int)

     :

     Returns a pseudorandom, uniformly distributed int value between 0 (inclusive) and the specified value (exclusive)

     So, just use Random.nextInt, passing N as the parameter, and add 1 to the result to get it 1 to N instead of 0 to (N-1).

     Check all answers on Stack Overflow

     3/5

   • Random number generator in java using seed

     Top Answer

     Answered Nov 21, 2016 · 1 votes

     There is a typo in your code, i should be j....

     for (j = 0; j < digits.size(); j++) { System.out.println(digits.get(i)); // <=== i should be j.}-

     I'd never mix i and j... and keep variables scoped to loops if possible.

     for (int index = 0; index < digits.size(); index++) { System.out.println(digits.get(index));}-

     and... if you're simply wanting to print results... consider java.util.Arrays.toString(int [] array)

     Check all answers on Stack Overflow

     4/5

   • Random number generator with range in Java

     Top Answer

     Answered Mar 06, 2016 · 3 votes

     Java's primitive byte is a data type is an 8-bit signed two's complement integer.

     That means the minimum value is -128 (-2^7) and the maximum value is 127 (inclusive)(2^7 -1)

     if you need or want a range between 0 and 255 you will need to correct the random number by yourself.

     And btw, Random class must be initialized before you do something like:

     rnd.nextBytes(a);

     Check all answers on Stack Overflow

     5/5

   Show moreShow less

2. stackoverflow.com › questions › 363681How do I generate random integers within a specific range in ...

   stackoverflow.com › questions › 363681

   • Cached

   The int nextInt(int origin, int bound) method was added in Java 17 as part of the RandomGenerator interface. This will generate a random integer in a given range: // Returns a random int between minimum (inclusive) & maximum (exclusive) int randomNum = RandomGenerator.getDefault().nextInt(minimum, maximum);

   Code sample

   public static int randInt(int min, int max) {

     Random rand;

     int randomNum = rand.nextInt((max - min) + 1) + min;

     return randomNum;

   }...

   See more on stackoverflow

3. www.geeksforgeeks.org › generating-random-numbersGenerating random numbers in Java - GeeksforGeeks

   www.geeksforgeeks.org › generating-random-numbers

   • Cached

   Feb 28, 2023 · Random class is used to generate pseudo-random numbers in java. An instance of this class is thread-safe. The instance of this class is however cryptographically insecure. This class provides various method calls to generate different random data types such as float, double, int. Constructors: Random(): Creates a new random number generator Random

4. www.w3schools.com › java › java_howto_random_numberJava How To Generate Random Numbers - W3Schools

   www.w3schools.com › java › java_howto_random_number

   • Cached

   How To Generate a Random Number. You can use Math.random() method to generate a random number. Math.random() returns a random number between 0.0 (inclusive), and 1.0 (exclusive):

5. www.freecodecamp.org › news › generate-randomJava Random Number Generator – How to Generate Integers With ...

   www.freecodecamp.org › news › generate-random

   • Cached

   Nov 25, 2020 · In this article, we will learn how to generate pseudo-random numbers using Math.random() in Java. 1. Use Math.random() to Generate Integers. Math.random() returns a double type pseudo-random number, greater than or equal to zero and less than one. Let's try it out with some code:

6. stackoverflow.com › questions › 5887709Getting random numbers in Java - Stack Overflow

   stackoverflow.com › questions › 5887709

   • Cached

   May 5, 2011 · The first solution is to use the java.util.Random class: import java.util.Random; Random rand = new Random(); // Obtain a number between [0 - 49]. int n = rand.nextInt(50); // Add 1 to the result to get a number from the required range // (i.e., [1 - 50]). n += 1; Another solution is using Math.random(): double random = Math.random() * 49 + 1 ...

7. www.baeldung.com › java-generating-random-numbersGenerating Random Numbers in Java | Baeldung

   www.baeldung.com › java-generating-random-numbers

   • Cached

   Jan 8, 2024 · The random method of the Math class will return a double value in a range from 0.0 (inclusive) to 1.0 (exclusive). Let’s see how we’d use it to get a random number in a given range defined by min and max: int randomWithMathRandom = (int) ((Math.random() * (max - min)) + min); 2.2. java.util.Random

8. People also ask

   How to generate random integers in Java 8?

   • With Java 8 they introduced the method ints(int randomNumberOrigin, int randomNumberBound) in the Random class. For example if you want to generate five random integers (or a single one) in the range [0, 10], just do:

   How do I generate random integers within a specific range in Java

   stackoverflow.com/questions/363681/how-do-i-generate-random-integers-within-a-specific-range-in-java

   See all results for this question

   What is randomgenerator in Java?

   • 1 - RandomGenerator is a modern interface that was introduced in Java 17. It is a common protocol for objects that generate random or pseudorandom sequences of numbers and has more features and methods than Random. Is there a reason why the example includes a .parallel()?

   How do I generate random integers within a specific range in Java

   stackoverflow.com/questions/363681/how-do-i-generate-random-integers-within-a-specific-range-in-java

   See all results for this question

   How do I generate a random number between two numbers?

   • To generate a random number "in between two numbers", use the following code: This gives you a random number in between 1 (inclusive) and 11 (exclusive), so initialize the upperBound value by adding 1. For example, if you want to generate random number between 1 to 10 then initialize the upperBound number with 11 instead of 10.

   How do I generate random integers within a specific range in Java

   stackoverflow.com/questions/363681/how-do-i-generate-random-integers-within-a-specific-range-in-java

   See all results for this question

   How to generate random numbers of double type?

   • Math.random method : Can Generate Random Numbers of double type. For using this class to generate random numbers, we have to first create an instance of this class and then invoke methods such as nextInt (), nextDouble (), nextLong () etc using that instance.

   Generating random numbers in Java - GeeksforGeeks

   www.geeksforgeeks.org/generating-random-numbers-in-java/

   See all results for this question

9. www.baeldung.com › java-generating-random-numbersGenerating Random Numbers in a Range in Java | Baeldung

   www.baeldung.com › java-generating-random-numbers

   • Cached

   May 11, 2024 · We can also use an instance of java.util.Random to do the same. Let’s make use of the java.util.Random.nextInt method to get a random number: Random random = new Random (); return random.nextInt(max - min) + min; The min parameter (the origin) is inclusive, whereas the upper bound max is exclusive.