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  1. May 15, 2010 · Thus, \d+ means match one or more digits. For example, the string "42" is matched by the pattern \d+.

  2. Dec 24, 2012 · Expanding on minitech's answer: ( start a capture group. \d a shorthand character class, which matches all numbers; it is the same as [0-9] + one or more of the expression. ) end a capture group. / a literal forward slash. Here is an example:

    Code sample

    >>> foo = re.match('\d+/(\d+)','1234/5678')
    >>> foo.groups()
    ('5678',)
  3. Oct 15, 2016 · If you want to enter an expression inside [], you need to use it as [^ expression]. + will match the preceding element one or more times. Eg: qw+e matches qwe, qwwe, qwwwwe, etc... Note: this is different from * as * matches preceding element zero or more times. i.e. qw*e matches qe as well.

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  5. Apr 24, 2013 · \d+ Means: \d means a digit (Character in the range 0-9), and + means 1 or more times. So, \d+ is 1 or more digits. \d++ Means from Quantifiers. This is called the possessive quantifiers and they always eat the entire input string, trying once (and only once) for a match.

  6. Dec 27, 2010 · If it is in a regular expression ( match or replace or split) or a / ... / string then it probably means match any digit 0-9. Please provide the code you see it in so we can be sure. answered Dec 27, 2010 at 19:14. 700 Software.

  7. Your regex ([A-Z]{2,3}\\d+) will match. Two or three letters A-Z, followed by a backslash "\", and finally one or more instances of the letter "d".

  8. Nov 6, 2017 · a. \d implies digit. b. + sign implies one or more occurance of previous character. c. \. -> since . is a special character in regex, we have to escape it with \. d. Also, \ is a special escape character in java , hence from java perspective we need to add an additional \ to escape the backslash (\). Thus, the pattern will reprent any number ...