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      Physical law of buoyancy

      • Archimedes’ principle, physical law of buoyancy, discovered by the ancient Greek mathematician and inventor Archimedes, stating that any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant, force, the magnitude of which is equal to the weight of the fluid displaced by the body.
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  2. Sep 12, 2022 · Archimedes’ Principle. The buoyant force on an object equals the weight of the fluid it displaces. In equation form, Archimedes’ principle is \[F_{B} = w_{fl},\] where F B is the buoyant force and w fl is the weight of the fluid displaced by the object.

  3. May 17, 2023 · Archimedes’ principle is a law of physics fundamental to fluid dynamics. It states that the upward buoyant force exerted on a body immersed in a fluid, whether wholly or partially submerged, is equal to the weight of the fluid that the body displaces.

    • Overview
    • What does buoyant force mean?
    • What is Archimedes' principle?
    • What's confusing about the buoyant force and Archimedes' principle?
    • Example 1: (an easy one)
    • Example 2: (a slightly harder one)
    • Example 3: (an even harder one)

    Why the heck do things float?

    What does buoyant force mean?

    Have you ever dropped your swimming goggles in the deepest part of the pool and tried to swim down to get them? It can be frustrating because the water tries to push you back up to the surface as you're swimming downward. The name of this upward force exerted on objects submerged in fluids is the buoyant force.

    So why do fluids exert an upward buoyant force on submerged objects? It has to do with differences in pressure between the bottom of the submerged object and the top. Say someone dropped a can of beans in a pool of water.

    [Not again!]

    Because pressure (Pgauge=ρgh)‍  increases as you go deeper in a fluid, the force from pressure exerted downward on the top of the can of beans will be less than the force from pressure exerted upward on the bottom of the can.

    Have you ever dropped your swimming goggles in the deepest part of the pool and tried to swim down to get them? It can be frustrating because the water tries to push you back up to the surface as you're swimming downward. The name of this upward force exerted on objects submerged in fluids is the buoyant force.

    So why do fluids exert an upward buoyant force on submerged objects? It has to do with differences in pressure between the bottom of the submerged object and the top. Say someone dropped a can of beans in a pool of water.

    [Not again!]

    Because pressure (Pgauge=ρgh)‍  increases as you go deeper in a fluid, the force from pressure exerted downward on the top of the can of beans will be less than the force from pressure exerted upward on the bottom of the can.

    Essentially it's that simple. The reason there's a buoyant force is because of the rather unavoidable fact that the bottom (i.e. more submerged part) of an object is always deeper in a fluid than the top of the object. This means the upward force from water has to be greater than the downward force from water.

    [Hold on..what if?]

    The way you will normally see the buoyant force formula written is with the g‍  and the V‍  rearranged like so,

    Fbuoyant=ρVfg‍ 

    When you rearrange the formula in this way it allows you to notice something amazing. The term ρVf‍  is the density of the displaced fluid multiplied by the volume of the displaced fluid. Since the definition of density ρ=mV‍  can be rearranged into m=ρV‍ , that means the term ρVf‍  corresponds to the mass of the displaced fluid. So, if we wanted to, we could replace the term ρVf‍  with mf‍  in the previous equation to get,

    Fbuoyant=mfg‍ 

    But look at that! The mass of the displaced fluid times the magnitude of the acceleration due to gravity is just the weight of the displaced fluid. So remarkably, we can rewrite the formula for the buoyant force as,

    Fbuoyant=Wf‍ 

    Sometimes people forget that the density ρ‍  in the formula for buoyant force Fb=ρVfg‍  is referring to the density of the displaced fluid, not the density of the submerged object.

    People often forget that the volume in the buoyancy formula refers to the volume of the displaced fluid (or submerged volume of the object), and not necessarily the entire volume of the object.

    Sometimes people think the buoyant force increases as an object is brought to deeper and deeper depths in a fluid. But the buoyant force does not depend on depth. It only depends on volume of the displaced fluid Vf‍ , density of the fluid ρ‍ , and the acceleration due to gravity g‍ .

    Many people, when asked to state Archimedes' principle, usually give a look of confused exasperation before launching into a wandering discussion about people jumping naked out of bathtubs. So, make sure you understand Archimedes' principle well enough to state it clearly: "Every object is buoyed upwards by a force equal to the weight of the fluid the object displaces."

    A 0.650 kg‍  garden gnome went snorkeling a little too low and found himself at the bottom of a fresh water lake of depth 35.0 m‍  . The garden gnome is solid (with no holes) and takes up a total volume of 1.44×10−3 m3‍  . The density of fresh water in the lake is 1000kgm3‍  .

    What is the buoyant force on the gnome?

    Fb=ρVg(Use buoyant force equation, which is just Archimedes’ principle in math form)‍ 

    Fb=(1000kgm3)(1.44×10−3 m3)(9.8ms2)(Plug in numerical values)‍ 

    A cube, whom you have developed a strong companionship with, has a total mass of 2.33kg‍  .

    What must be the minimum side length of the cube so that it floats in sea water of density 1025kgm3‍ ?

    We know that in order to float the buoyant force when the object is submerged must be equal to the magnitude of the weight of the cube. So we put this in equation form as,

    Wcube=Fb(Weight of cube equals magnitude of buoyant force)‍ 

    mg=ρVg(Plug in expressions for the weight of the cube and buoyant force)‍ 

    mg=ρL3g(Insert the formula for the volume of a cube L3)‍ 

    A huge spherical helium filled balloon painted to look like a cow is prevented from floating upward by a rope tying it to the ground. The balloon plastic structure plus all the helium gas inside of the balloon has a total mass of 9.20 kg‍  . The diameter of the balloon is 3.50 m‍  . The density of the air is 1.23kgm3‍  .

    What is the tension in the rope?

    This one is a little harder so we should first draw a free body diagram (i.e. force diagram) for the balloon. There are lots of numbers here too so we could include our known variables in our diagram so that we can see them visually. (Note that in this case, the fluid being displaced is the air.)

    Since the spherical cow balloon is not accelerating, the forces must be balanced (i.e. no net force). So we can start with a statement that the magnitudes of the total upward and downward forces are equal.

    Fb=W+FT(Upward and downward forces are equal/balanced)‍ 

    ρVg=mg+FT(Insert the formulas for buoyant force and weight of balloon respectively)‍ 

  4. Archimedes' principle (also spelled Archimedes's principle) states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces.

  5. Archimedes’ principle refers to the force of buoyancy that results when a body is submerged in a fluid, whether partially or wholly. The force that provides the pressure of a fluid acts on a body perpendicular to the surface of the body.

  6. Archimedes principle: The buoyant force on the ship (a) is equal to the weight of the water displaced by the ship—shown as the dashed region in (b). The principle can be stated as a formula: \[\mathrm{F_B=w_{fl}}\]

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