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  1. Jan 23, 2021 · Push Or Pull. “Using a puller fan is seen as a better practice,” says Brent Chuck, application engineer at SPAL USA. “Mounting the fan in front of the radiator adds a restriction to airflow through the system. So, it’s seen as a better practice to put the fan on the engine side and add the restriction after the radiator.

  2. The pusher, puller, and reversible-style fans are the available options. The pusher-style fan mounts on the front of the radiator, and as its name indicates, it pushes airflow through the radiator. However, its mounting location blocks about 20 percent of airflow.

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  4. Push / puller or reversible fans (SPAL fans are not reversible) On SPAL fans the last letter of the part number denotes if the fan is a pusher (blowing) or puller (suction): The pusher style mounts on the front of the radiator toward the front of the vehicle and pushes air flow back into the radiator.

  5. Aug 9, 2023 · Check alternator output, I would not use anything less than a 100 amp Alt. Especially when using an electric fan, you need full fan rpms to cool. You will need to use upgraded alternator wiring if upgrading to a 100 amps. verify ignition timing, might have moved or a wearing dist gear is retarding the timing.

  6. Oct 21, 2016 · Chevy86. 15 posts · Joined 2017. #13 · Jan 31, 2017. Looks like your problem is fixed but wanted to throw an idea at you. I also have a Spal fan, works great but as added protection I installed a small pusher fan wired separate in front of the radiator with a probe type sensor. I also wired it hot even with key off.

  7. Sep 17, 2004 · Basic electricity laws will allow you to reverse the polarity of the fan, thus reversing the motor rotation, however, if you looked at the blades on the SPAL itself, you'll notice they were designed specifically to either "push" or "pull" with maximum efficiency in which they were made.

  8. Jan 4, 2018 · But if we start off with all reactants and no product, then the forward direction is spontaneous. The meaning of reversible. The short answer is that for chemical reactions, "reversible" does not have a precise thermodynamic definition. $$dG = dG^\circ + RT \ln Q = -RT \ln K + RT \ln Q = RT \ln \frac{Q}{K}$$ where $K$ is the equilibrium constant.

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