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Jan 17, 2019 · "The Confirmation Polarization" is the thirteenth episode of the twelfth season of the American sitcom The Big Bang Theory. The episode aired on Thursday, January 17, 2019. When Sheldon and Amy's Super-Asymmetry theory is proven by two physicists, Greg Pemberton and Kevin Campbell from Chicago...
Jan 17, 2019 · With Johnny Galecki, Jim Parsons, Kaley Cuoco, Simon Helberg. Sheldon and Amy are thrilled when their super asymmetry theory is proven by two physicists, until they try to kick Amy off the Nobel nomination. Bernadette gets one of her drugs approved and wants a reluctant Penny to head the sales team.
- (2.4K)
- Comedy, Romance
- Mark Cendrowski
- 2019-01-17
Jan 8, 2019 · The Confirmation Polarization Season 12, Episode 13 - Aired January 17, 2019 Sheldon and Amy are thrilled when two physicists from Fermilab prove their theory of super asymmetry, but their joy dissipates when Doctors Pemberton and Campbell try to take credit for the work.
Jan 22, 2019 · In the episode — " The Confirmation Polarization " — Sheldon and Amy receive an email from Fermilab. Two scientists had confirmed Amy and Sheldon's theory called Super Asymmetry. The...
19 min. TV-PG. Sheldon and Amy's super asymmetry theory is proven by two physicists, Dr. Pemberton and Dr. Campbell from Chicago, who then try to kick Amy off the Nobel nomination. Bernadette has a big success at work and Penny's going to be a part of it-whether she wants to or not. Available Episodes. S12 | E13 19 min. NOW PLAYING. UP NEXT.
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Jan 8, 2019 · The Confirmation Polarization – When Sheldon and Amy’s super asymmetry theory is proven by two physicists, Dr. Pemberton (Sean Astin) and Dr. Campbell (Kal Penn) from Chicago, they’re thrilled, until they try to kick Amy off the Nobel nomination.
The Confirmation Polarization Season 12, Episode 13 - Aired January 17, 2019 Sheldon and Amy are thrilled when two physicists from Fermilab prove their theory of super asymmetry, but their joy dissipates when Doctors Pemberton and Campbell try to take credit for the work.