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Jul 20, 2022 · The instantaneous power of a constant applied force is the product of the component of the force in the direction of motion and the instantaneous velocity of the moving object.
Jul 20, 2022 · 1. The direction and magnitude of static friction on an object always depends on the direction and magnitude of the applied forces acting on the object, where the magnitude of kinetic friction for a sliding object is fixed. 2. The magnitude of static friction has a maximum possible value.
Sep 25, 2021 · The answer is that you can't. You can't have a force that exerts constant power if velocity is 0. The best you could do is say the force is "infinite" at that point, but it's really a breakdown of the constraints. The constraints simply exclude v=0 $\endgroup$ –
8.3 Constraint Forces. Knowledge of all the external and internal forces acting on each of the objects in a system and applying Newton’s Second Law to each of the objects determine a set of equations of motion. These equations of motion are not necessarily independent due to the fact that the motion of the objects may be limited by equations ...
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What is the instantaneous power of a constant applied force?
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In order to find the instantaneous power at any time, we need to find the instantaneous velocity at that time. The ball takes a time . t. f = 1.4 s to reach the height . y. f = 5.0 m . The velocity at that height is given by . v. y = −. gt . f = −(9.8 m ⋅ s )(1.4 s) = −1.4 × 10 m ⋅ s-1 . (13.7.11) So the instantaneous power at time ...
If the power is constant over a time interval, the average power for that interval equals the instantaneous power, and the work done by the agent supplying the power is W = PΔt W = P Δ t. If the power during an interval varies with time, then the work done is the time integral of the power, W = ∫Pdt. W = ∫ P d t.
If the power is constant over a time interval, the average power for that interval equals the instantaneous power, and the work done by the agent supplying the power is W = P Δt W = P Δ t. If the power during an interval varies with time, then the work done is the time integral of the power, W = ∫ P dt. W = ∫ P d t.
