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  1. Barium Iodide formula and structure. The chemical formula of Barium iodide is BaI 2 and its molar mass is 391.136 g/mol. Moreover, the structure of its anhydrous form resembles that of lead (II) chloride with each Ba center bound to nine iodide ligands and has a crystalline packing structure that is quite similar to BaCl 2.

  2. Barium acetate, upon heating, decomposes to carbonate. It reacts with sulfuric acid to give sulfate, hydrochloric acid to give chloride, and nitric acid to give nitrate. Hazards. The chemical compound is harmful if swallowed or inhaled. Applications. The chemical compound finds application as a mordant for printing textile fabrics.

  3. Aug 10, 2023 · On A+ the answer's 233.4 =] The molar mass of the sulfate ion is approximately 96 g/mol. molecular weight for barium nitrate. 137.33 grams per mole. 233.4.

  4. The balanced chemical equation is as follows: 2CH3CH2CO2H(aq) + Ca(OH)2(aq) → (CH3CH2CO2)2Ca(aq) + 2H2O(l) The reaction of a weak acid and a strong base will go to completion, so it is reasonable to prepare calcium propionate by mixing solutions of propionic acid and calcium hydroxide in a 2:1 mole ratio.

  5. Aug 13, 2023 · A barium milkshake is a suspension of very fine BaSO 4 particles in water; the high atomic mass of barium makes it opaque to x-rays. from Wikipedia. A Rubidium hydroxide and cobalt(II) chloride are strong electrolytes, so when aqueous solutions of these compounds are mixed, the resulting solution initially contains Rb + , OH − , Co 2 + , and ...

  6. It has a molar mass of 261.337 g / mol, a density of 3.24 g / cm 3 and a melting point of 592 ° C. When it reaches its boiling point, it decomposes, as mentioned above. At room temperature it has a solubility in water of 10.5 g / 100 ml. It is considered stable, but it is a strong oxidizing agent and must be kept away from combustible ...

  7. Nov 21, 2013 · You can only report two sig figs, because the mass of sodium sulfate has been measured to only the tenths place; 2.0 is only two sig figs. There will be some leftover barium nitrate in the solution. The concentration of each remaining ion (Ba 2+ , Na + , and NO 3 – in solution could be calculated, but that's another problem.

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