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  1. The 1988 United States presidential election was the 51st quadrennial presidential election held on Tuesday, November 8, 1988. Incumbent Republican Vice President George H. W. Bush defeated the Democratic Massachusetts Governor Michael Dukakis.

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      The 1988 United States presidential election in Iowa took...

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  2. In the 1988 presidential election, Republican Vice President George H. W. Bush defeated Democratic Governor Michael Dukakis of Massachusetts. Bush won the popular vote by just under eight points, and won 426 of the 538 electoral votes.

    • November 8
    • Ronald Reagan (Republican)
    • Republican hold
    • 101st
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  4. Eugene McCarthy. Dan Quayle. Lloyd Bentsen. Ron Paul. David Duke. (Show more) United States presidential election of 1988, American presidential election held on Nov. 8, 1988, in which Republican George Bush defeated Democrat Michael Dukakis. The campaign. Michael Dukakis, 1988.

  5. The 1988 United States presidential election happened on November 8, 1988. George H. W. Bush, the Republican candidate and Vice President of the United States, won the election. He defeated the Democratic candidate, Governor Michael Dukakis of Massachusetts.

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  6. George Bush. Change History! 1988 interactive map. << 1984 1992 >> The United States election of 1988 featured an open primary for both major parties. Ronald Reagan, the incumbent President, was vacating the position after serving the maximum two terms allowed by the Twenty-second Amendment.

  7. 178889 United States presidential election; Party Candidate Votes % Independent: George Washington: 43,782 100% Federalist: John Adams (vice president) n/a n/a Federalist: John Jay: n/a n/a Federalist: Robert H. Harrison: n/a n/a Federalist: John Rutledge: n/a n/a Federalist: John Hancock: n/a n/a Anti-Administration: George Clinton: n/a n/a ...

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