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The precise strength of Earth's gravity varies with location. The agreed upon value for standard gravity is 9.80665 m/s 2 (32.1740 ft/s 2) by definition. [4] This quantity is denoted variously as gn, ge (though this sometimes means the normal gravity at the equator, 9.7803267715 m/s 2 (32.087686258 ft/s 2 )), [5] g0, or simply g (which is also ...
Jan 27, 2016 · The acceleration of gravity (also referred to as the gravitational field strength) at the surface of the earth has an average of 9.807 m/s^2, which means that an object dropped near earth's surface will accelerate downward at that rate. Gravity is a force, and according to Newton's Second Law, a force acting on an object will cause it to accelerate: F=ma Acceleration is a rate of change of ...
Apr 7, 2004 · The value of 9.8m/s^2 is considered the constant acceleration due to gravity because it is the average acceleration of an object falling towards the Earth's surface. This value was first calculated by Galileo in the 16th century through experiments with free-falling objects. 2.
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The value 9.8 m/s² is valid for the object at the surface of earth (at sea level). When height is small (with respect to radius of earth), the value is slightly less than 9.8 m/s². So, this variation can be neglected for a high school etc problems. When accuracy is important (due to scientific reasons etc), the value of g can't be 9.8 m/s².
- No, the value $9.8\\frac{\\mathrm{m}}{\\mathrm{s}^2}$ is an approximation that is only valid at or near the Earth's surface. You can go a few miles up...
- To expand a little on David's point assume we move from the nominal "surface" where $g$ is $9.8\\text{ m}/\\text{s}^2$ to another point at radius $...
- $g$ becomes $ g \\approx 9.7 \\frac{m}{s^2}$ at a height of about 35km, so it would be ok to use the value $9.81$ for "down to earth" problems. The...
- It might also be worth mentioning that $g$ isn't even constant over the earth's surface at sea level. Depending on the mass distribution and the sh...
- The approximation of 9.81 m/s^2 is a generalisation. The exact value is most likely different at a specific location, due to the distance from the...
- Acceleration due to gravity, g is not a universal constant like G. Its calculated by formula mentioned in previous answers. So, for a constant mass...
- As we go above or below the surface of earth the value of g decreases since g is inversely proportional to height
Because of gravity, a falling object's speed increases by 9.81 m/s every second. This meters per second per second quantity is written as m/s 2. Gravity pulls more the closer you are to an object, this means objects get faster and faster as they get closer. When speed increases this is called acceleration.
The 9.8 m/s^2 is the acceleration of an object due to gravity at sea level on earth. You get this value from the Law of Universal Gravitation. Force = m*a = G (M*m)/r^2. Here you use the radius of the earth for r, the distance to sea level from the center of the earth, and M is the mass of the earth.
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- Sal Khan
9.8 meters per second per second (yes, that is two lots of "per second") can be written 9.8 m/s/s, but is usually written: 9.8 m/s 2. 9.8 m/s 2 is the acceleration due to gravity near the Earth's surface. Nearly everything in our lives happens near the Earth's surface, so that value gets used a lot, and is written as a little g: g = 9.8 m/s 2
