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-x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim _{x\to 0}(x\ln (x)) \int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx \sum_{n=0}^{\infty}\frac{3}{2^n} Show More
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x→−3lim x2 + 2x − 3x2 − 9. Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.
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Oct 25, 2016 · Explanation: The given function is differentiated by using chain rule because it is a composite function of absolue value and polynomial function. Let. u(x) = 4 +3f (x) and v(x) = √x. Then h(x) = v(u(x)) h'(x) = v(u(x))'. h'(x) = v'(u(x)) ⋅ u'(x)
Mar 15, 2015 · One solution is $f(x)=\sin(x),$ from the identity $$\sin(3x)=3\sin(x)-4\sin^3(x)\tag{1}$$ which can be checked using the addition formula for sine. Analytic solutions are (I think) only constants and those of the form $\pm \sin(kx).$ Sketch: Assume $f$ is a nonconstant solution.
