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1. Top results related to is 1492 a leap year python

   • Python: To check whether a given year is a leap year or not?

     Top Answer

     Answered Nov 13, 2022 · 0 votes

     Let's step through your code for 2024:

     • year%4==0 is True, so we enter the if block
     • year%100!=0 is also True, so we enter the if block again.

     And now you check for year%400==0. Um, why? 2024 isn't a century, so it can never be a multiple of 400. So your logic is broken here. 2024 is divisible by 4 and not divisible by 100. At this point we can simply return True!

     Where we need to check for divisibility by 400 is in the next case (where year%100!=0 is False).

     If we take all of this, we get this code:

     def is_leap(year): if(year%4==0): if(year%100!=0): return True else: if(year%400==0): return True else: return False else: return False-

     (note how I got rid of the completely unnecessary variable.)

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   • Python how to check if it is a leap year with ==int

     Top Answer

     Answered Nov 01, 2017 · 1 votes

     Your issue is that int is a type. If you try to compare a number to a type of object, which is what you are doing when you write if year/400 == int :, it will always return False, because these can never be the same.

     A better way to check if year/400 is an integer would be:

     if year%400 == 0: return False

     This is saying: If the remainder of year/400 is equal to 0, return False, which is what you wanted.

     Some other things are:

     You should use elif instead of if in most cases. In this one, it doesn't matter, since the return statement terminates the execution of the function early, but you should still use it anyways. Otherwise, even when you have your final result, it will go through the rest of the if statements.

     The other thing isn't related to your code, but your leap year criteria are incorrect. If the year is divisible by 4, then it's a leap year. Unless the year is divisible by 100, then it's not. Unless it's divisible by 400, then it is.

     Improved code:

     def leapyear(year): if year%400 == 0: return True elif year%100 == 0: return False elif year%4 == 0: return True return False

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     2/5

   • How can I check if a year is a leap year using Python?

     Top Answer

     Answered May 10, 2020 · 4 votes

     Divisibility by 400 is an exception to the rule that years divisible by 100 are not leap years, which itself is an exception to the rule that years divisible by 4 are leap years. If you wrote it out in sequence, you might write

     if year % 400 == 0: # Some centuries are leap years... print("leap year")elif year % 100 == 0: # ... but most are not ... print("not leap year")elif year % 4 == 0: # ... even though other divisibly-by-four years are print("leap year")else: print("not leap year")

     or work your way up

     if year % 4 != 0: print("not a leap year")elif year % 100 != 0: print("leap year")elif year % 400 != 0: print("not a leap year")else: print("leap year")

     Combining these into a single test would be something like

     if year % 4 != 0 or (year % 100 == 0 and year % 400 != 0): print("not a leap year")else: print("leap year")

     which I find a little harder to follow than a series of simple tests.

     (Given the nature of a solar year, making every year divisible by 400 a leap year is also a problem, though not as big a one as making every century year a leap year. People wanting to avoid drifts over the millenia will propose additional exceptions like "years divisible by 4000, or 40,000, or something, should not be leap years"; no official rule exists yet, though.)

     Other Answers

     Answered May 10, 2020 · 1 votes

     Because 1900 % 4 is actually 0, so the first if conditional is True ( True or False is True) and then it doesn't execute the second if block because is an elif (else if, and since the first was True, there is no need to execute the else part).

     Other Answers

     Answered Jul 27, 2020 · 1 votes

     Try like this!

     year = int(input("Input year: "))-if year % 4 == 0: print("Year is leap.") if year % 100 == 0 and year % 400 != 0: print("Year is common.")else: print("Year is common.")

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   • Python | Pandas DatetimeIndex.is_leap_year

     Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.

     Pandas DatetimeIndex.is_leap_year attribute return a boolean indicator if the date belongs to a leap year. A leap year is a year, which has 366 days (instead of 365) including 29th of February as an intercalary day. Leap years are years which are multiples of four with the exception of years divisible by 100 but not by 400.

     Syntax: DatetimeIndex.is_leap_year

     Returns: numpy array containing logical values.

     Example #1: Use DatetimeIndex.is_leap_year attribute to check if the dates present in the DatetimeIndex object belongs to a leap year.

     # importing pandas as pd import pandas as pd   # Create the DatetimeIndex didx = pd.DatetimeIndex(['2014-01-01', '2008-12-31', '2017-03-31', '2000-12-31'])   # Print the DatetimeIndex print(didx)

     Output :

     Now we want to find if the dates contained in the given DatetimeIndex object belongs to a leap year or not.

     # find if the dates belong to leap year didx.is_leap_year -

     Output : ...

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   • Python | Pandas PeriodIndex.is_leap_year

     Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.

     Pandas PeriodIndex.is_leap_year attribute return an array of boolean values corresponding to each element in the PeriodIndex object. It return True if the given year is a leap year else it return False if it is not a leap year.

     Syntax : PeriodIndex.is_leap_year

     Parameters : None

     Return : array of boolean values

     Example #1: Use PeriodIndex.is_leap_year attribute to check for each element in the given PeriodIndex object, whether it is a leap year or not.

     # importing pandas as pd import pandas as pd   # Create the PeriodIndex object pidx = pd.PeriodIndex(start ='2003-12-21 08:45 ',               end ='2009-12-21 11:55', freq ='Y')   # Print the PeriodIndex object print(pidx)

     Output :

     Now we will use the PeriodIndex.is_leap_year attribute to check if the given year is a leap year or not.

     # check for leap year pidx.is_leap_year -

     Output :

     As we can see in the output, the PeriodIndex.is_leap_year attribute has returned an...

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2. www.geeksforgeeks.org › python-program-to-check-ifPython Program to Check if given year is Leap Year ...

   www.geeksforgeeks.org › python-program-to-check-if

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   Feb 8, 2024 · In this example, The code uses Python’s `calendar` module to determine whether a given year is a leap year by invoking the `isleap` function. In the provided example, the year 2024 is checked. Python3. import calendar. def is_leap_year_calendar(year): return calendar.isleap(year) # Example. year_to_check = 2024.

3. stackoverflow.com › questions › 11621740python - How to determine whether a year is a leap year ...

   stackoverflow.com › questions › 11621740

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   Jul 24, 2012 · The year can be evenly divided by 4, is a leap year, unless: The year can be evenly divided by 100, it is NOT a leap year, unless: The year is also evenly divisible by 400. Then it is a leap year. This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years. source

   Code sample

   import calendar

   print(calendar.isleap(1900))

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4. www.programiz.com › examples › leap-yearPython Program to Check Leap Year

   www.programiz.com › examples › leap-year

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   print("{0} is a leap year".format(year)) # if not divided by both 400 (century year) and 4 (not century year) # year is not leap year else: print("{0} is not a leap year".format(year)) Run Code. Output. 2000 is a leap year. You can change the value of year in the source code and run it again to test this program. Also Read:

5. www.tutorialgateway.org › python-program-to-checkPython Program to Check Leap Year or Not - Tutorial Gateway

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   • Python Program to Check Leap Year Using If Statement
   • Python Leap Year Program Using Calendar Module
   • Python Program to Check Leap Year Using Elif Statement
   • Python Program to Check Leap Year Using Nested If Statement
   • Python Program to Check Leap Year Program in Python Using Functions

   This Python program allows the user to enter any number and check whether the user entered is a leap year or not using the If statement. In this Python leap year program, we used Logical AND and Logical OR operators Since we have to check multiple conditions within one If Statement. Let us divide the condition to understand it better 1: ( yr%400 ==...

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   This program imports the calendar module and uses the isleap() function to determine whether the given year is a leap.

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   It allows the user to enter any value. Then, this program code will check whether the user entered is Leap year or not using the Elif Statement. In this Python elif program, first, the User will enter any number to check whether that is Leap Year or Not. 1. First, the If condition will check whether the (ya % 400) reminder is exactly equal to 0. As...

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   This leap year program uses nested if statement to check the lear year. It allows the user to enter any number, and then it will check using the Nested Ifstatement. This Python program allows users to enter any value to check whether that is a Leap year. First, the If condition will check whether the remainder of the (num%4) is exactly equal to 0. ...

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   This function accepts any integer, and using the if else statement, it checks the condition and finds out whether it is a leap year.

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6. pythonguides.com › python-program-to-check-leap-yearLeap Year Program in Python using Function

   pythonguides.com › python-program-to-check-leap-year

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   May 9, 2024 · Leap Year Program in Python using Function. What is a leap year in Python? A leap year is a year that is completely divisible by 4. This year has 366 days and one extra day, but remember, if the year is like 100, then it should also be divisible by 400. Also, if the year is divisible by 4 and not divisible by 100, then that is considered a leap ...

7. note.nkmk.me › en › python-calendar-leap-yearDetermine, count, and list leap years in Python | note.nkmk.me

   note.nkmk.me › en › python-calendar-leap-year

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   Jan 31, 2024 · In Python, the calendar module provides functions to determine if a year is a leap year and to count leap years in a specified period. calendar — General calendar-related functions — Python 3.12.1 documentation

8. People also ask

   How to check if a year is a leap year in Python?

   • In this example, The code uses Python’s `calendar` module to determine whether a given year is a leap year by invoking the `isleap` function. In the provided example, the year 2024 is checked. In this example, the lambda function `is_leap_year_lambda` checks if a given year is a leap year using a concise expression with the modulo operator.

   Python Program to Check if given year is Leap Year

   www.geeksforgeeks.org/python-program-to-check-if-given-year-is-leap-year/

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   Is the century divisible by 400 a leap year?

   • If the century is divisible by 400, that is a Leap year. If it is not divisible by 400, then that is not. This Python program allows the user to enter any number and check whether the user entered is a leap year or not using the If statement. print("%d is a Leap year" %yr) print("%d is Not" %yr)

   Python Program to Check Leap Year or Not - Tutorial Gateway

   www.tutorialgateway.org/python-program-to-check-leap-year/

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   How to write a Python program for leap year using function?

   • To get the year input from the user, the function is modified by adding this line ‘year = int (input (“Enter the year: “))’ at the beginning of the function to get the input from the user. This is how to write a Python program for leap year using function with user Input.

   Leap Year Program In Python Using Function - Python Guides

   pythonguides.com/python-program-to-check-leap-year/

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   Is a year divisible by 4 a leap year?

   • If a year is divisible by 4, it is a leap year. However, if that year is divisible by 100, it is not a leap year, unless… It is also divisible by 400, in which case, it is a leap year. Expressed in mathematical form, the conditions can be written as follows: Below, are the methods for Python programs to Check If A Given Year Is a Leap Year.

   Python Program to Check if given year is Leap Year

   www.geeksforgeeks.org/python-program-to-check-if-given-year-is-leap-year/

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9. blog.finxter.com › 5-best-ways-to-check-for-a-leap5 Best Ways to Check for a Leap Year in Python Using datetime

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   Feb 28, 2024 · Method 1: Using calendar.isleap () The calendar.isleap() function is a straightforward method provided by Python’s standard library which returns True if the year is a leap year, and False otherwise. This function takes an integer value representing the year as its parameter. Here’s an example: