Search results
The Deutsch–Jozsa algorithm is a deterministic quantum algorithm proposed by David Deutsch and Richard Jozsa in 1992 with improvements by Richard Cleve, Artur Ekert, Chiara Macchiavello, and Michele Mosca in 1998.
Jan 28, 2021 · Jan 28, 2021. 247. A thorough guide to the Deutsch-Jozsa Algorithm in practice, including a overview and explanation of the mathematics, a complete Circuit, and an example implementation in...
People also ask
What is Deutsch algorithm?
What is the difference between Deutsch-Jozsa algorithm and classical algorithm?
What is the Deutsch Jozsa algorithm?
Which Deutsch algorithm is implemented in IBM-Q with a constant quantum Oracle?
Mar 4, 2021 · The Deutsch algorithm is a quantum algorithm capable of determining the value of \ (f_ {i} (0) \oplus f_ {i} (1)\) by making only a single query to a quantum oracle for \ (f\). The oracle can be expressed as a unitary operator. \ [U_ {f} | x>_ {A} | y >_ {B} = | x >_ {A} | y \oplus f (x) >_ {B}\] fromqiskitimportQuantumCircuit,QuantumRegister ...
Thus, Deutsch’s problem is equivalent to evaluating f(0) f(1). It turns out that by a clever twist of the naive approach above, we can indeed evaluate f(0) f(1) (without individually obtaining the values f(0), f(1)) via Deutsch’s algorithm. 3.2 Deutsch’s algorithm The circuit for Deutsch’s algoritm is given as follows. jq1i = j0i H Uf H LL
- 236KB
- 9
Flowchart of using successive subtractions to find the greatest common divisor of number r and s. In mathematics and computer science, an algorithm ( / ˈælɡərɪðəm / ⓘ) is a finite sequence of mathematically rigorous instructions, typically used to solve a class of specific problems or to perform a computation. [1]
Examples of high-level programming languages in active use today include Python, JavaScript, Visual Basic, Delphi, Perl, PHP, ECMAScript, Ruby, C#, Java and many others. The terms high-level and low-level are inherently relative.
Mar 4, 2022 · Now, let us turn to the Deutsch problem. It is a special case of the Deutsch–Jozsa problem with n = 1. Therefore, the oracle maps f : {0, 1}↦ {0, 1}. It only has 1 bit of input and thus it only has two possible inputs (either “0” or “1”). As a result, it only has two possible outputs ( f (0) and f (1)).
