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- - Document Type Declaration must appear only once
  Top Answer
  Answered Dec 12, 2014 · 4 votes
  Check and see if there is a layout file. If you using the template for MVC that Visual Studio provides then your layout file will be located at Views/Shared/_Layout. There you can see that <!DOCTYPE html> has already been inserted.
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- DOCTYPE's role in general XML
  Top Answer
  Answered Jul 30, 2009 · 6 votes
  DOCTYPE has been "inherited" from SGML (it was supposed to point to DTD file that explains how to parse the file), however self-explanatory XML syntax and namespaces made it largely irrelevant. The only real use for DOCTYPE/DTD in XML is to define allowed named entities (e.g.  ).
  XML spec even allows "non-validating" parsers that ignore DTD file completely (web browsers use such parsers, unless you've fallen into the text/html trap in which case XML parser is not used at all).
  DTD is quite poor for purpose of validation (hard to specify rules for more than one level of nesting, no way to specify types of attributes beyond few predefined types). Schema, RelaxNG can be far more precise.
  DTD doesn't fully suppport namespaces either, which leads to ridiculous workarounds like XHTMLplusMathMLplusSVG DOCTYPE.
  In web browsers certain DOCTYPEs have desirable side-effect of triggering standards-compliant rendering mode. This is more of a hack than intended use DOCTYPEs.
  If you're using real XHTML ( application/xhtml+xml – the one that doesn't open in IE at all), then don't use DOCTYPE at all (that's recommendation from XHTML 5). XML mode will trigger standards-compliant rendering regardless of DOCTYPE.
  If you're using text/html mode, then use <!DOCTYPE html> . That's HTML 5 DOCTYPE and it's a shortest one that triggers best possible rendering in all browsers. Browsers don't use DOCTYPE for any other purpose, so you're not missing out on anything.
  If you're processing XHTML files with XML parsers (outside browsers), then please don't forget to set up DTD Catalog properly, otherwise your parser may be DoS-ing w3.org trying to fetch DTD every time. If you can't use DTD catalog, then disable "externals" in the parser or omit DOCTYPE and don't use named entities (i.e. use   rather than   )
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- XML DOM doctype Property
  Example
  The following code fragment loads "note_internal_dtd.xml" into xmlDoc and returns a DocumentType object:
  var xhttp = new XMLHttpRequest();xhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { myFunction(this); }};xhttp.open("GET", "note_internal_dtd.xml", true);xhttp.send();function myFunction(xml) { var xmlDoc = xml.responseXML; document.getElementById("demo").innerHTML = xmlDoc.doctype;}
  
  Output:
  [object DocumentType]
  
  Definition and Usage
  The doctype property returns the Document Type Declaration associated with the document.
  For XML documents without a DTD this returns null.
  This provides direct access to the DocumentType object (a child node of this Document).
  Syntax
  documentObject.doctype
  
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  3/5
- How to Delete/Remove DOCTYPE Declaration from the XML Document?
  Top Answer
  Answered May 10, 2011 · 6 votes
  This seems to do what you want :
  try { XMLInputFactory inFactory = XMLInputFactory.newFactory(); XMLOutputFactory outFactory = XMLOutputFactory.newFactory();- XMLEventReader input = inFactory.createXMLEventReader( new FileInputStream("test.xml")); XMLEventReader filtered = inFactory.createFilteredReader( input, new DTDFilter()); XMLEventWriter output = outFactory.createXMLEventWriter( System.out); output.add(filtered); output.flush();}catch (XMLStreamException e) { e.printStackTrace();}catch (FileNotFoundException e) { e.printStackTrace();}static class DTDFilter implements EventFilter{ @Override public boolean accept(XMLEvent event) { return event.getEventType() != XMLStreamConstants.DTD; }}
  
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- XML Declaration standalone="yes" lxml
  Top Answer
  Answered Feb 25, 2020 · 25 votes
  You can pass standalone keyword argument to tostring():
  etree.tostring(tree, pretty_print = True, xml_declaration = True, encoding='UTF-8', standalone=True)-
  
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www.w3schools.com › xml › xml_dtdXML DTD - W3Schools

www.w3schools.com › xml › xml_dtd
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Valid XML Documents. A "Valid" XML document is "Well Formed", as well as it conforms to the rules of a DTD: The DOCTYPE declaration above contains a reference to a DTD file. The content of the DTD file is shown and explained below.
en.wikipedia.org › wiki › Document_type_declarationDocument type declaration - Wikipedia

en.wikipedia.org › wiki › Document_type_declaration
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A document type declaration, or DOCTYPE, is an instruction that associates a particular XML or SGML document (for example, a web page) with a document type definition (DTD) (for example, the formal definition of a particular version of HTML 2.0 - 4.0).
People also ask
What is XML document type declaration?
The XML Document Type Declaration, commonly known as DTD, is a way to describe XML language precisely. DTDs check vocabulary and validity of the structure of XML documents against grammatical rules of appropriate XML language. An XML DTD can be either specified inside the document, or it can be kept in a separate document and then liked separately.

XML - DTDs - Online Tutorials Library

www.tutorialspoint.com/xml/xml_dtds.htm
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What is a DOCTYPE in XML?
DOCTYPE is part of the XML specification (see the relevant subsection here) and can include either a link to a DTD, "internal" DTD declarations, or both. Many "modern" uses of XML don't use a DOCTYPE at all, though - as porneL mentions, both XML Schema and RelaxNG are more powerful ways to specify a document's syntax.

html - DOCTYPE's role in general XML - Stack Overflow

stackoverflow.com/questions/1209763/doctypes-role-in-general-xml
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What is a document type declaration?
A document type declaration, or DOCTYPE, is an instruction that associates a particular XML or SGML document (for example, a web page) with a document type definition (DTD) (for example, the formal definition of a particular version of HTML 2.0 - 4.0 ).

Document type declaration - Wikipedia

en.wikipedia.org/wiki/Document_type_declaration
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How do I declare a DTD in XML?
The DTD can either be internal (written into the same document that it's being used in), or external (located in another document). You declare a DTD at the top of your XML document (in the prolog) using the !DOCTYPE declaration. The basic syntax is: ...where, rootname is the root element, and [ DTD] is the actual definition.

DTD - Quackit Tutorials

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www.w3.org › wiki › Choosing_the_right_doctype_forChoosing the right doctype for your HTML documents

www.w3.org › wiki › Choosing_the_right_doctype_for
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Mar 10, 2014 · In this Web Standards Curriculum article I will look at the doctype in a lot more detail, showing what it does and how it helps you validate your HTML, how to choose a doctype for your document, and the XML declaration, which you’ll rarely need, but will sometimes come across.
www.tutorialspoint.com › xml › xml_dtdsXML - DTDs - Online Tutorials Library

www.tutorialspoint.com › xml › xml_dtds
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Learn how to use DTDs to describe XML language precisely and check the structure of XML documents. See the basic syntax, internal and external DTDs, and types of identifiers.
www.w3.org › Consortium › OfficesXML, the DTD - slide "Document Type Declaration"

www.w3.org › Consortium › Offices
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Document Type Declaration. <!DOCTYPE RootName SYSTEM URL> <!DOCTYPE RootName PUBLIC "PublicID" URL (optional)> <!DOCTYPE RootName [ the declarations of the DTD ]> The DTD goes after the XML declaration or is in a separate file: <?xml version="1.0"?> <!DOCTYPE exam SYSTEM "exam.dtd"> Remember:
stackoverflow.com › questions › 1209763html - DOCTYPE's role in general XML - Stack Overflow

stackoverflow.com › questions › 1209763
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Jul 30, 2009 · DOCTYPE's role in general XML. Asked 14 years, 10 months ago. Modified 14 years, 10 months ago. Viewed 942 times. 0. I know the purpose of DOCTYPE (and what each url/identifier on the line is) as far as web standards and page validation goes, but I am unsure about what it actually "is" in the context of an XML document.
www.quackit.com › xml › tutorialDTD <!DOCTYPE> - Quackit Tutorials

www.quackit.com › xml › tutorial
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You declare a DTD at the top of your XML document (in the prolog) using the !DOCTYPE declaration. The basic syntax is: xxxxxxxxxx. <!DOCTYPE rootname [DTD]> ...where, rootname is the root element, and [ DTD] is the actual definition.

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www.w3schools.com › xml › xml_dtdXML DTD - W3Schools

en.wikipedia.org › wiki › Document_type_declarationDocument type declaration - Wikipedia

XML - DTDs - Online Tutorials Library

html - DOCTYPE's role in general XML - Stack Overflow

Document type declaration - Wikipedia

DTD - Quackit Tutorials

www.w3.org › wiki › Choosing_the_right_doctype_forChoosing the right doctype for your HTML documents

www.tutorialspoint.com › xml › xml_dtdsXML - DTDs - Online Tutorials Library

www.w3.org › Consortium › OfficesXML, the DTD - slide "Document Type Declaration"

stackoverflow.com › questions › 1209763html - DOCTYPE's role in general XML - Stack Overflow

www.quackit.com › xml › tutorialDTD <!DOCTYPE> - Quackit Tutorials

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