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15 Tricks to Guess Correct Answers for MCQs in JEE Main & JEE Advanced. 1) Steer away from the Highest and the Lowest. In questions which have answers in numerical values, stay away from the extremes. In 60% cases, the highest and the lowest values are not the correct answers. 2) Gamble on One of the Two Options.
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- Molarity
- Normality
- Equivalent Mass
- Dilution Effects
- Volume Strength of H2O2 Solution
- Percentage Labeling of Oleum
- Related Resources
It is defined as the number of moles of solute present in one litre of solution. Molarity (M) = Let the weight of solute be w g, molar mass of solute be M1g/mol and the volume of solution be V litre. Number of moles of solute = Hence M Hence Number of moles of solute
It is defined as the number of equivalents of a solute present in one litre of solution. Equivalent is also the term used for amount of substance like mole with the difference that one equivalent of a substance in different reactions may be different as well as the one equivalent of each substance is also different. Normality (N) =
Equivalents mass = Hence Number of equivalents of solute Hence Number of equivalents of solute = n × number of moles of solute Also, N = M × n Hence Where n is n- factor or valency factor here.
When a solution is diluted, the moles and equivalents of solute do not change but molarity and normality changes while on taking out a small volume of solution from a larger volume, the molarity and normality of solution do not change but moles and equivalents change proportionately. In stoichiometry, the biggest problem is that for solving a probl...
When a solution of H2O2 is labeled as ‘x volume’, it means that 1 volume (1 ml of 1 litre) of H2O2 solution would liberate x volumes (1 ml or 1 litre) of O2at STP on complete decomposition. H2O2 H2O + ½O2…….. (i) If a H2O2 solution (acting as reducing agent) has normality N and its is to be reacted with KMnO4 solution (acting as oxidizing agent). O...
Oleum contains H2SO4 and SO3 only. When oleum is diluted (by adding water), SO3 reacts with H2O to form H2SO4, thus increasing the mass of the solution. SO3 + H2O → H2SO4 The total mass of H2SO4obtained by diluting 100 g of oleum sample with required amount of water, is equal to the percentage labeling of oleum. Percentage labeling of oleum = Total...
Look here for past year papers of IIT JEEClick here to refer syllabus of chemistry for IIT JEEYou can also have a look at gravimetric analysisDec 20, 2018 · grade and 0-and is the grade of disease as pe r . disease rating scale. ... Fig.2 2A an d 2B, Graphical representation of plant disease incidence of all the varieties in the .
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