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1. Top results related to eight function of dictionary in java tutorial

   • Dictionary of ArrayLists in Java

     Top Answer

     Answered Jun 05, 2012 · 2 votes

     Instead of ArrayList grades; you'd have to use ArrayList grades = new ArrayList();

     Yet better: ArrayList<Float> grades = new ArrayList<Float>(); //or use Double or Number

     Note that unlike C or C++ creating a variable doesn't create the object as well. In C++ you could imagine your code as ArrayList* grades; i.e. you'd just create the reference/pointer here.

     Additional thoughts:

     • Dictionary studentGrades; this will be initialized to null.
     • public void main(String[] args) that's not a valid main function since it would have to be static
     • if you have a public static void main(String[] args) you can't use this since you don't have an object instance in the static context
     • You can't instantiate Dictionary since it is abstract. Use one of its subclasses, e.g. new Hashtable<String, List<Float>>(), or a map, e.g. Map<String, List<Float> dictionary = new HashMap<String, List<Float>>();
     • Note that local primitive variables are also not initialized, so this could give you an error too: boolean res; In Java only class members are initialized, local variables are not.

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   • Dictionary sorting of ArrayList of Arraylist in java

     Top Answer

     Answered Mar 23, 2019 · 2 votes

     Comparator functions that contain 1 or -1 are error prone.

     Instead, you should write it like this:

     public static int lexicographically(List<Integer> a, List<Integer> b) { for (int i = 0, end = Math.min(a.size(), b.size()); i < end; i++) { int res = Integer.compare(a.get(i), b.get(i)); if (res != 0) return res; } return Integer.compare(a.size(), b.size());}

     This style of writing comparator functions prevents various common mistakes, such as never returning 0.

     The most important pattern in this style is:

     • Compare by the first criterion.
     • If the given values differ, return the comparison result and be done.
     • Take the next criterion, continue with step 1.
     • If there are no criteria left, return 0.

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     2/5

   • Eight queens in Java in recursion

     Top Answer

     Answered Nov 25, 2012 · 0 votes

     In Java, when you pass the object to the method, you copy the reference to the object. So, changes made to the object are visible by all references to that object (including the one you keep in the calling method).

     There are two solutions for it:

     • Copy the HashSet before doing modifications, and do the modifications to the copy. In case a solution is found, return the new copy. In case it does not work, return the original copy.
     • Use a data structure thtat depends in an index, so you can ignore all values that should not still be set. For example an array, if you are iterating for the 5th queen you can ignore the values of the fifth, sixth, seventh and eighth queens if they are set.

     I find more clear the queens problem implemented with an int array, but that is left to everybodys taste.

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     3/5

   • Function of jxl.jar in java

     Top Answer

     Answered May 09, 2011 · 1 votes

     jxl.jar is the library of JExcelApi , which is a open source java API to read, write, and modify Excel spreadsheets dynamically. It contains all the compiled *.class files, associated metadata and resources that are used by the Java Excel API internally .

     Java library are distributed as a .jar file .You can refer to this for more info about JAR.

     As the official API of JExcelApi does not contain a file called jxl.java .I believe this is the Java class created by you to test the function of JExcelApi . To use the JExcelApi , you have to import the necessary classes from the jxl.jar and specified jxl.jar to be on the class path when you compile jxl.java .

     So , the connection between jxl.java and jxl.jar is that jxl.java calls the classes from jxl.jar to manipulate the Excel.

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     4/5

   • In Java why we need an object to call a function in the main function of the same class but no object for other function which is not main?

     Top Answer

     Answered Mar 12, 2020 · 1 votes

     Because the main method is outside the class and so you have to create an instance of the class with which you can access the methods of the class

     and if your main method is within the class, you can use the methods in the main method without creating an object, but your methods must be static

     Also check this please Java OOP

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     5/5

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2. www.youtube.com › watchJAVA 8 Features Tutorial | Functional Interfaces | Lambda ...

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   4 days ago · Java 8 Version introduced a significant number of features that changed the way developers write Java applications. Here are some of the key features:Default...

3. www.geeksforgeeks.org › strings-in-javaStrings in Java - GeeksforGeeks

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   4 days ago · Ways of Creating a String. There are two ways to create a string in Java: String Literal. Using new Keyword. Syntax: <String_Type> <string_variable> = "<sequence_of_string>"; . 1. String literal. To make Java more memory efficient (because no new objects are created if it exists already in the string constant pool).

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   35 Basic Java Program Examples with Outputs - pwskills.com

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5. www.geeksforgeeks.org › basic-string-operationsBasic String Operations with Implementation - GeeksforGeeks

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   3 days ago · In this post, we will look into some of the basic String operations such as: Accessing characters by index in a string. Inserting character into a String. Modifying character in String. Deletion of Character in String. Concatenating strings (combining multiple strings into one). Finding the length of a string.

6. www.geeksforgeeks.org › functions-programmingFunctions in Programming - GeeksforGeeks

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7. www.youtube.com › watchJava Tutorial For Beginners 3 - Keywords Explained Step by ...

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   4 days ago · Video Description:In this video, we dive into the world of programming with Java and take a closer look at keywords in Java. We will explore how to effective...

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8. stackoverflow.com › questions › 78405623Convert `(String, Int)...` variadic parameter function to ...

   stackoverflow.com › questions › 78405623

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   5 days ago · But this doesn't work for the Dictionary. The existing initializer is expecting a [String : Int] dictionary, but the ExpressibleByDictionaryLiteral function parameter is a (String, Int)... Why do these "expressible by Array/Dictionary literal" give you a variadic parameter in the first place, rather than an array/dictionary?

9. pwskills.com › blog › basic-java-program-examples35 Basic Java Program Examples with Outputs - pwskills.com

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   5 days ago · Basic Java Program Examples With Outputs. 1) Hello World Program: 2) Addition of Two Numbers: 3) Find Maximum of Three Numbers: 4) Check Even or Odd Number: 5) Factorial of a Number: 6) Print Pattern in Java: 7) Add Two Binary Numbers in Java: 8) Add Two Complex Numbers in Java: