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  1. In 1903, at the age of 26, Hesse falls in love, in Basle, with Maria Bernoulli, 9 years older than him. Maria is a free-lance photographer and is the first woman in Switzerland to have a studio in the old town. Moreover she is a talented musician. Together they set out on journeys and frequent the artistic circles in Basle.

  2. Hermann Hesse was born in Calw in the Black Forest in the German state of Wüttenberg on July 2, 1877. His father, Johannes Hesse, was born in Weissenstein, Estonia, and retained Russian citizenship. His mother, Marie Gundert, was born to Pietist missionaries in Talatscheri, India. In 1880, Hesse's family moved to Basle, a city located on the ...

  3. physics. The Bernoulli family ( / bɜːrˈnuːli / bur-NOO-lee, German: [bɛʁˈnʊli], [a] Swiss Standard German: [bɛrˈnʊli]) of Basel was a patrician family, notable for having produced eight mathematically gifted academics who, among them, contributed substantially to the development of mathematics and physics during the early modern period .

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  5. In probability and statistics, a Bernoulli process (named after Jacob Bernoulli) is a finite or infinite sequence of binary random variables, so it is a discrete-time stochastic process that takes only two values, canonically 0 and 1. The component Bernoulli variables Xi are identically distributed and independent.

  6. Jul 5, 2018 · Downloadable version. Solving two step equations – PowerPoint. Solving two step equations – Worksheet. 5. Alternative versions. feel free to create and share an alternate version that worked well for your class following the guidance here.

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  7. bernoulli\:y'+\frac{4}{x}y=x^3y^2 ; bernoulli\:y'+\frac{4}{x}y=x^3y^2,\:y(2)=-1 ; bernoulli\:y'+\frac{4}{x}y=x^3y^2,\:y(2)=-1,\:x>0 ; bernoulli\:6y'-2y=xy^4,\:y(0)=-2 ; bernoulli\:y'+\frac{y}{x}-\sqrt{y}=0,\:y(1)=0 ; Show More

  8. Let us check this out. Bernoulli’s equation must be used since the depth is not constant. We consider water flowing from the surface (point 1) to the tube’s outlet (point 2). Bernoulli’s equation as stated in previously is [latex]{P}_{1}+\frac{1}{2}{{\rho v}_{1}}^{2}+\rho gh_{1}={P}_{2}+\frac{1}{2}{{\rho v}_{2}}^{2}+\rho gh_{2}\\[/latex].

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