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  1. What Is the Formula for Area of the Segment of a Circle? The area of the segment of the circle (or) minor segment of a circle is: (θ / 360°) × πr 2 - (1/2) r 2 sin θ (OR) r 2 [πθ/360° - sin θ/2], if 'θ' is in degrees

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    • What Is A Segment of A Circle
    • Types of Segment in A Circle
    • Formulas

    A segment of a circle is the region bounded by a chord of the circle and its associated arc. It is represented by the symbol ‘⌓’. A semicircle is the biggest segment of a circle. In the given circle, the segment is enclosed by the chord AB and its associated arc ACB.

    There are two types of segments in a circle: minor and major segment. A segment with an intercepted arc less than the semicircle is called a minor segment, while a segment with an intercepted arc more than the semicircle is called a major segment. If nothing specifically is stated, a segment means the minor segment.

    The formula to find the area of the segment of a circle can either be expressed in terms of degree or in terms of radians. The two formulas for calculating circle’s segment are given below.

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  3. The formula to find segment area can be either in terms of radians or in terms of degree. The formulas for a circle’s segment are as follows: Area of a Segment of a Circle Formula. Formula To Calculate Area of a Segment of a Circle. Area of a Segment in Radians. A = (½) × r 2 (θ – Sin θ) Area of a Segment in Degrees.

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  4. A circle has an angle of 2 π and an Area of: πr2. A Sector has an angle of θ instead of 2 π so its Area is : θ 2π × πr2. Which can be simplified to: θ 2 × r2. Area of Sector = θ 2 × r 2 (when θ is in radians) Area of Sector = θ × π 360 × r 2 (when θ is in degrees)

  5. What is the midpoint of line segment A B ― ‍ ? An x- y- coordinate plane where the x and y tick marks scale by one. A line segment A B has endpoint A at negative six, eight and endpoint B is at six, negative seven.

  6. Feb 14, 2022 · \(a^{2}+b^{2}=c^{2}\) Substitute in the values. \(3^{2}+4^{2}=d^{2}\) Simplify. \(9+16=d^{2}\) \(25=d^{2}\) Use the Square Root Property. \(d=5\quad\cancel{d=-5}\) Since distance, \(d\) is positive, we can eliminate \(d=-5\). The distance between the points \((6,4)\) and \((2,1)\) is \(5\). Table 11.1.1

  7. Area of Segments Formula. Let AB be a chord of circle with radius r. Let ∠ AOB = θ and 0 < θ 180. The minor segment corresponding to chord AB is shown in figure. Area of Minor Segment = Area of sector OAB – Area of triangle OAB. Since area of sector = θ 360 π r 2 and. area of triangle = 1 2 r 2 s i n θ.

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