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Algebra. Solve for G H^2=mG+qG. H 2 = mG + qG H 2 = m G + q G. Rewrite the equation as mG+qG = H 2 m G + q G = H 2. mG+qG = H 2 m G + q G = H 2. Factor G G out of mG+qG m G + q G. Tap for more steps... G(m+q) = H 2 G ( m + q) = H 2. Divide each term in G(m+q) = H 2 G ( m + q) = H 2 by m +q m + q and simplify. Tap for more steps...
mg g; 1: 0.001: 2: 0.002: 3: 0.003: 4: 0.004: 5: 0.005: 6: 0.006: 7: 0.007: 8: 0.008: 9: 0.009: 10: 0.01: 11: 0.011: 12: 0.012: 13: 0.013: 14: 0.014: 15: 0.015: 16: 0.016: 17: 0.017: 18: 0.018: 19: 0.019: 20: 0.02: 21: 0.021: 22: 0.022: 23: 0.023: 24: 0.024: 25: 0.025: 26: 0.026: 27: 0.027: 28: 0.028: 29: 0.029: 30: 0.03: 31: 0.031: 32: 0.032: ...
To illustrate this idea, consider the production of ammonia by reaction of hydrogen and nitrogen: N 2(g) + 3H 2(g) → 2NH 3(g) This equation shows that ammonia molecules are produced from hydrogen molecules in a 2:3 ratio, and stoichiometric factors may be derived using any amount (number) unit:
How many NH 3 molecules are produced by the reaction of 4.0 mol of Ca (OH) 2 according to the following equation: (NH4)2SO4 + Ca(OH)2 2NH3 + CaSO4 + 2H2O ( NH 4) 2 SO 4 + Ca ( OH) 2 2 NH 3 + CaSO 4 + 2 H 2 O. Answer: 4.8 × × 10 24 NH 3 molecules. These examples illustrate the ease with which the amounts of substances involved in a chemical ...
1 g = 1000 mg 1 mg = 0.001 g. Example: convert 15 g to mg: 15 g = 15 × 1000 mg = 15000 mg. Popular Weight And Mass Unit Conversions
Example 4.4.4 4.4. 4: Determining A Molecular Formula from Mole Ratios. If 1.5875 g of copper react with 0.8875 g of chlorine to form copper chloride, write the chemical formula for the copper chloride. Step 1: Determine the number of moles of an element which reacted. In this case, Cu.
We can divide both sides of this expression by either side to get one of two possible conversion factors: 1mol Al 26.98g Al and 26.98g Al 1 mol Al 1 m o l A l 26.98 g A l a n d 26.98 g A l 1 m o l A l. The first conversion factor can be used to convert from mass to moles, and the second converts from moles to mass.
