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  3. boolean leap = false; // if the year is divided by 4 if (year % 4 == 0) {. // if the year is century if (year % 100 == 0) {. // if year is divided by 400 // then it is a leap year if (year % 400 == 0) leap = true; else. leap = false; // if the year is not century else. leap = true;

    • Using Scanner Class
    • Using Ternary Operator
    • Using In-Built Isleap() Method

    Here the user is provided the flexibility to enter the year of their own choice as Scanner Class is imported here rest of the if-else blocks are also combined in a single statement to check if the input year is a leap year. Below is the Java program to implement the approach: Input Output

    Ternary Operator is used to reduce the if-else statements. The ternary operator takes three operands, a boolean condition, an expression to execute if the condition is true, and an expression to execute if false. Below is the Java program to implement the approach:

    Java has an in-built isLeap() method to check if the input year is a leap year or not. Below is the Java program to implement the approach:

    • 11 min
  4. Jan 8, 2024 · Since Java 1.1, the GregorianCalendar class allows us to check if a year is a leap year: public boolean isLeapYear(int year); As we might expect, this method returns true if the given year is a leap year and false for non-leap years.

  5. Apr 21, 2024 · a) If the year divisible by 400 then it prints the given year is leap or if the given year divisible by 4 and not divisible by 100 then it prints the given year is a leap. b) Otherwise, it prints “year is not a leap year”.

  6. FileName: LeapYear.java. public class LeapYear. { // a method that checks whether the. // year y is a leap year or not. boolean isLeapYr (int y) { // if condition that handles. // the century year. if( (y % 100) == 0) { if( (y % 400) == 0) { return true; } else. { return false; } // if condition that handles the. // non century year.

  7. import java.util.Scanner; public class lecture{ public static void main(String[] args) { boolean loop=true; Scanner console = new Scanner( System.in ); while (loop){ System.out.print( "Enter the year: " ); int year= console.nextInt(); System.out.println( "The year is a leap year: "+ leapYear(year) ); System.out.print( "again?: " ); int again ...

    Code sample

    public static boolean isLeapYear(int year) {
      Calendar cal = Calendar.getInstance();
      cal.set(Calendar.YEAR, year);
      return cal.getActualMaximum(Calendar.DAY_OF_YEAR) > 365;
    }
  8. Nov 28, 2023 · A year is a leap year if the following conditions are satisfied: The year is multiple of 400. The year is a multiple of 4 and not a multiple of 100. Leap year or not. Program to Check Leap Year Using Macros. Here we will use macros to check the leap year. In macros, we will use the necessary condition to check the leap year and return the answer.

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