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1. Top results related to generate list of random numbers python program

   • Program to generate a random length list of random numbers in Python

     Top Answer

     Answered Aug 21, 2018 · 1 votes

     You have done most part of it.

     In order to create a new list in makelist with a length equal to the random int you got in main(), you have to pass that number via arguments, like the code below.

     Also, you have to assign makelist to return to a variable in main, so that you can use whatever output makelist has produced. This can be done simply via var = makelist(random_int). I called this variable elements.

     Finally, there are a few options to sort the list. One of them is to use Python's built-in function sorted and pass the final list as argument. Iterate over it and print each value.

     import random-def main(): random_int = random.randint(6, 12) print (random_int) elements = makelist(random_int) for i in sorted(elements): print (i,)-def makelist(random_int): num_list = [] for count in range(random_int): num_list.append(random.randint(1, 100)) return num_list-main()-

     Other Answers

     Answered Aug 21, 2018 · 2 votes

     Another solution:

     from random import randint-def makelist(count): return [randint(1, 100) for _ in range(count)]-def main(): random_integer = randint(6, 12) # Generate a random integer where 5 < i < 13 print(random_integer) # Print this integer on its own line unsorted_list = makelist(count=random_integer) # Make a list sorted_list = sorted(unsorted_list) # Sort the list print(' ' . join([str(i) for i in sorted_list])) # Print it out-main()-

     The main thing to take away from this is that makelist returns a list comprehension, which is totally not necessary to use. You should have quite enough with all these answers to figure it out.

     David is right, of course. makelist doesn't need to exist, although it does serve to add a bit of readability to the exercise (and may be "required," as OP's guidelines suggest). You could just as easily go all the way with something like:

     from random import randint-count = randint(6, 12)print(count)print(' ' . join([str(i) for i in sorted([randint(1, 100) for _ in range(count)])]))-

     It depends on how deep your particular rabbit hole goes. I certainly wouldn't turn that in to the professor...

     Other Answers

     Answered Aug 21, 2018 · 1 votes

     If you just want a better version of your existing program, I have fixed your code and compressed it into a single function below. However, I think it is more constructive to edit what you have already written rather than redoing it - see the rest of my answer for details on fixing your code.**

     from random import randint-def main(): random_int = random.randint(6, 13) print(random_int) rand_list = [randint(1, 100) for _ in range(random_int)] return sorted(rand_list)-print main()-

     In main, generate a random integer that is greater than 5 and less than 13.

     • [" random_int "," should be assigned to random.randint(6, 12) "," as the randint function uses inclusive range parameters"]

     Call the makelist function with the random integer as sole argument.

     • ["Your make_list ","function currently takes no arguments, so let's change it's definition to def make_list(list_lengh): ",". Now we can pass in the random integer from main() "," as input."]

     use a loop to append to the list a number of elements equal to the random integer argument.

     • ["In the second line of code in the make_list function "," you are calling range with default arguments of (1, 101) ",", which isn't what you want. You want to call range on list_length "," because you want to loop the same number of times as the random integer created in main() ","."]

     All new list elements must be random integers ranging from 1 to 100, inclusive.

     • ["You don't want num_list.append(random_int) ",". That will simply give you the [random_int]*random_int ",". Instead append random.randint(1, 101) ","."]

     Finally, use a for loop to display the sorted list elements, all on one line

     • There are a number of ways you could do this, but since you want to print all of the integers onto one line, let's append the integers to a string with a loop and then return the string at the end.

     Like so:

     num_string = ""for i in sorted(rand_list): num_string += str(i) + " "return num_string-

     Once you have made all those revisions, you aren't to far from where you started, but the code now possesses the desired behavior.

     import random-def main(): random_int = random.randint(6, 13) print(random_int) rand_list = make_list(random_int) num_string = "" for i in sorted(rand_list): num_string += str(i) + " " return num_string-def make_list(list_length): num_list = [] for count in range(list_length): num_list.append(random.randint(1, 101)) return num_list-print main()-

     Example output:

     1020 63 63 71 78 83 83 84 87 94-

     Check all answers on Stack Overflow

     1/5

   • Generate a list of 6 random numbers between 1 and 6 in python

     Top Answer

     Answered Oct 07, 2018 · 13 votes

     Use a list comprehension:

     import random-def startTheGame():- mylist=[random.randint(1, 6) for _ in range(6)] return mylist

     List comprehensions are among the most powerful tools offered by Python. They are considered very pythonic and they make code very expressive.

     Consider the following code:

     counter = 0myList = []while (counter) < 6: randomNumber = random.randint(1, 6)-myList.append(randomNumber)counter = counter + 1if (counter)>=6: passelse: return

     We will refactor this code in several steps to better illustrate what list comprehensions do. First thing that we are going to refactor is the while loop with an initialization and an abort-criterion. This can be done much more concise with a for in expression:

     myList = []for counter in range(6): randomNumber = random.randint(1, 6)myList.append(randomNumber)-

     And now the step to make this piece of code into a list comprehension: Move the for loop inside mylist. This eliminates the appending step and the assignment:

     [random.randint(1, 6) for _ in range(6)]-

     The _ is a variable name just like any other, but it is convention in python to us e _ for variables that are not used. Think of it as a temp variable.

     Check all answers on Stack Overflow

     2/5

   • Python - Generate a list of 40 random numbers summing to 1, with min and max weight

     Top Answer

     Answered Dec 29, 2021 · 1 votes

     Perhaps using np.random.normal would give better results. You could scale down the distribution to the 0.005-0.045 range using the proportion of 80% that is variable (above 0.005). Because normal distributions can still have outliers, it will be necessary to "retry" the calculation if the values go out of bounds (but that shouldn't happen too frequently unless you give a large standard deviation):

     import numpy as np

     def randStock(count=40,minR=0.005,maxR=0.045,sd=3): iterations = 0 while True: iterations += 1 r = np.random.normal(1,sd,count) #normal distribution r -= min(r) # offset to zero r /= max(r) # scale to 0..1 r = minR + r/sum(r)*(maxR-minR)/(maxR+minR) # scale to range if min(r)>=minR and max(r)<=maxR: return r, iterations

     Output:

     for _ in range(10): s,i = randStock() print(*map("{:6.4f}".format,(sum(s),min(s),max(s))),i,"iterations")[sum] [min] [max] [mean] 1.0000 0.0050 0.0404 0.0250 1 iterations1.0000 0.0050 0.0409 0.0250 2 iterations1.0000 0.0050 0.0395 0.0250 1 iterations1.0000 0.0050 0.0411 0.0250 4 iterations1.0000 0.0050 0.0410 0.0250 2 iterations1.0000 0.0050 0.0428 0.0250 1 iterations1.0000 0.0050 0.0433 0.0250 1 iterations1.0000 0.0050 0.0424 0.0250 1 iterations1.0000 0.0050 0.0371 0.0250 1 iterations1.0000 0.0050 0.0446 0.0250 1 iterations

     Note that this could be improved to randomize the lower bound a bit more and you can chose a different standard deviations

     Check all answers on Stack Overflow

     3/5

   • Generate list of random names - Python

     Top Answer

     Answered Dec 01, 2016 · 6 votes

     you're just duplicating your string here. Random occurs only once.

     Do it in a generator comprehension instead, and join the results with space:

     import random-first_names=('John','Andy','Joe')last_names=('Johnson','Smith','Williams')group=" ".join(random.choice(first_names)+" "+random.choice(last_names) for _ in range(3))print(group)

     outputs:

     Joe Williams Joe Johnson Joe Smith-

     Other Answers

     Answered Aug 21, 2018 · 2 votes

     Another solution:

     from random import randint-def makelist(count): return [randint(1, 100) for _ in range(count)]def main(): random_integer = randint(6, 12) # Generate a random integer where 5 < i < 13 print(random_integer) # Print this integer on its own line unsorted_list = makelist(count=random_integer) # Make a list sorted_list = sorted(unsorted_list) # Sort the list print(' ' . join([str(i) for i in sorted_list])) # Print it outmain()

     The main thing to take away from this is that makelist returns a list comprehension, which is totally not necessary to use. You should have quite enough with all these answers to figure it out.

     David is right, of course. makelist doesn't need to exist, although it does serve to add a bit of readability to the exercise (and may be "required," as OP's guidelines suggest). You could just as easily go all the way with something like:

     from random import randint-count = randint(6, 12)print(count)print(' ' . join([str(i) for i in sorted([randint(1, 100) for _ in range(count)])]))

     It depends on how deep your particular rabbit hole goes. I certainly wouldn't turn that in to the professor...

     Other Answers

     Answered Aug 21, 2018 · 1 votes

     If you just want a better version of your existing program, I have fixed your code and compressed it into a single function below. However, I think it is more constructive to edit what you have already written rather than redoing it - see the rest of my answer for details on fixing your code.**

     from random import randint-def main(): random_int = random.randint(6, 13) print(random_int) rand_list = [randint(1, 100) for _ in range(random_int)] return sorted(rand_list)print main()

     In main, generate a random integer that is greater than 5 and less than 13.

     • [" random_int "," should be assigned to random.randint(6, 12) "," as the randint function uses inclusive range parameters"]

     Call the makelist function with the random integer as sole argument.

     • ["Your make_list ","function currently takes no arguments, so let's change it's definition to def make_list(list_lengh): ",". Now we can pass in the random integer from main() "," as input."]

     use a loop to append to the list a number of elements equal to the random integer argument.

     • ["In the second line of code in the make_list function "," you are calling range with default arguments of (1, 101) ",", which isn't what you want. You want to call range on list_length "," because you want to loop the same number of times as the random integer created in main() ","."]

     All new list elements must be random integers ranging from 1 to 100, inclusive.

     • ["You don't want num_list.append(random_int) ",". That will simply give you the [random_int]*random_int ",". Instead append random.randint(1, 101) ","."]

     Finally, use a for loop to display the sorted list elements, all on one line

     • There are a number of ways you could do this, but since you want to print all of the integers onto one line, let's append the integers to a string with a loop and then return the string at the end.

     Like so:

     num_string = ""for i in sorted(rand_list): num_string += str(i) + " "return num_string

     Once you have made all those revisions, you aren't to far from where you started, but the code now possesses the desired behavior.

     import random-def main(): random_int = random.randint(6, 13) print(random_int) rand_list = make_list(random_int) num_string = "" for i in sorted(rand_list): num_string += str(i) + " " return num_stringdef make_list(list_length): num_list = [] for count in range(list_length): num_list.append(random.randint(1, 101)) return num_listprint main()

     Example output:

     1020 63 63 71 78 83 83 84 87 94-

     Check all answers on Stack Overflow

     4/5

   • Generate random numbers from a list of numbers

     Top Answer

     Answered Jan 29, 2020 · 1 votes

     You can simply use np.random.choice:

     import numpy as np data=[15,30,45]N = 50new_list = np.random.choice(data,N)-

     Edit: Using random.sample() won't work as the sampling is done without replacement, therefore samples can't exceed length of the original data.

     Check all answers on Stack Overflow

     5/5

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2. www.geeksforgeeks.org › generating-random-numberGenerating random number list in Python - GeeksforGeeks

   www.geeksforgeeks.org › generating-random-number

   • Cached

   Aug 18, 2022 · Method 1: Using the random.randint () By using random.randint () we can add random numbers into a list. Python3. import random. rand_list=[] n=10. for i in range(n): rand_list.append(random.randint(3,9)) print(rand_list) Output. [9, 3, 3, 6, 8, 5, 4, 6, 3, 7] Method 2: Using random.sample ()

3. stackoverflow.com › questions › 16655089Python: Random numbers into a list - Stack Overflow

   stackoverflow.com › questions › 16655089

   • Cached

   You could use random.sample to generate the list with one call: import random my_randoms = random.sample(range(100), 10) That generates numbers in the (inclusive) range from 0 to 99. If you want 1 to 100, you could use this (thanks to @martineau for pointing out my convoluted solution): my_randoms = random.sample(range(1, 101), 10)

   Code sample

   import random

   my_randoms = [random.randrange(1, 101, 1) for _ in range(10)]

   See more on stackoverflow

4. codefather.tech › blog › create-list-of-randomHow to Create a List of Random Numbers in Python

   codefather.tech › blog › create-list-of-random

   • Cached

   Nov 26, 2023 · You can generate a list of random numbers by simply putting together a function provided by Python’s random module with a while loop. The following code uses the randint() function of Python’s random built-in module and a while loop to generate a list of random integers: >>> random_integers = [] >>> while len(random_integers) < 10:

5. docs.python.org › 3 › libraryrandom — Generate pseudo-random numbers — Python 3.12.3 ...

   docs.python.org › 3 › library

   • Cached

   1 day ago · Source code: Lib/random.py. This module implements pseudo-random number generators for various distributions. For integers, there is uniform selection from a range. For sequences, there is uniform selection of a random element, a function to generate a random permutation of a list in-place, and a function for random sampling without replacement.

6. pynative.com › python › randomPython Random Module: Generate Random Numbers and Data - PYnative

   pynative.com › python › random

   • Cached

   Jun 16, 2021 · Example. import random. print("Printing random number using random.random()") print(random.random()) # Output 0.5015127958234789. Run. As you can see in the result, we have got 0.50. You may get a different number. The random.random() is the most basic function of the random module.

7. datagy.io › python-random-numberGenerate Random Numbers in Python • datagy

   datagy.io › python-random-number

   • Cached

   Mar 2, 2022 · Python makes it very easy to generate random numbers in many different ways. In order to do this, you’ll learn about the random and numpy modules, including the randrange, randint, random, and seed functions. You’ll also learn about the uniform and normal functions in order to create more controlled random values.

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   How to generate a list of random numbers in Python?

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