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1. Top results related to how is java different from other programming languages?

   • How is a union different from a struct? Do other languages have similar constructs?

     Top Answer

     Answered Nov 16, 2009 · 11 votes

     So in your example, when I allocate time:

     int main(){ time t;}-

     The compiler can interpret the memory at &t as if it is either a long:

     t.simpleDate;-

     or as if its a double:

     t.perciseDate;-

     So if the raw hex of the memory at t looks like

     0x12345678;-

     That value can be "parsed" as either a double or long, depending on how its accessed. So for it to be useful you have to know how a long and a double are going to be packed & formatted exactly in memory. For example, a long is going to be a 2-s complement signed integer, which you can read about here. you can learn how a double is formatted in binary here.

     A struct, however, just groups separate variables, with distinct address spacing into one block of memory.

     (Note your example might be dangerous as sizeof(long) could be 32 bits whereas sizeof(double) is always 64 bits)

     Unions are commonly used when you want a "raw" representation (like a char array) and a "message" representation. For example a message that is to be sent over a socket:

     struct Msg{ int msgType; double Val1; double Val2;}; // assuming packing on 32-bit boundaryunion{ Msg msg; unsigned char msgAsBinary[20];};

     Hope that helps.

     Other Answers

     Answered Nov 16, 2009 · 14 votes

     A union behaves as if all its members are in the same location in memory, overlapping.

     This is useful when you want to represent some kind of "generic" value, or a value that can be of any of a set of types. Because the fields overlap, you can only legally access a field if you know it's been previously initialized. Still, since C doesn't check this, and many compilers emit code that allow it, it is a common trick to do ... interesting type conversions, such as:

     union { int integer; float real;} convert;-convert.real = 3.14;printf("The float %f interpreted as an integer is %08x", convert.real, convert.integer);

     For the more well-formed usage, where you keep track of what was last stored in the union, it could look for instance like this:

     typedef enum { INTEGER = 0, REAL, BOOLEAN, STRING } ValueType;-typedef struct { ValueType type; union { int integer; float real; char boolean; char *string; } x;} Value;

     Here, note that the union is actually a field in the surrounding structure, Value. Access could look like this:

     void value_set_integer(Value *value, int x){ value->type = INTEGER; value->x.integer = x;}

     This records that the current contents of the union is an integer, and stores the given value. A function to e.g. print a Value can inspect the type member, and do the right thing:

     void value_print(const Value *value){ switch(value->type) { case INTEGER: printf("%d\n", value->x.integer); break; case REAL: printf("%g\n", value->x.real); break; /* ... and so on ... */ }}

     There is no equivalent in Java. C++, being sort of almost a super-set of C, has the same functionality. It even "one-ups" C's implementation, and allows anonymous unions. In C++, the above could have written without naming the inner union (x), which would make the code quite a lot shorter.

     Other Answers

     Answered Nov 16, 2009 · 2 votes

     A union lets you interpret one memory location (raw, binary value) in several different ways.

     An example I've actually used, is accessing the individual bytes of a uint32.

     union { uint32 int; char bytes[4];} uint_bytes;-

     What a union offers, is multiple ways of accessing (parts of) the same memory.

     The size of a union type is equal to the size of the largest type in the union.

     Check all answers on Stack Overflow

     1/5

   • How is CompileTime classpath different from RunTime classpath in Java?

     What is a Classpath? Classpath refers to the Path where all the classes/jars are available.

     What is Compile-time classpath? This classpath has all the classes/jars required to compile the application without any syntax error.

     Now we might think that our project compiled successfully so it will execute nicely. But this is not always true why because in some cases(explained below) to execute the project successfully you may need some other class/jars at runtime. That is why run-time classpath comes into the picture.

     What is Run-time classpath? Classpath that has all the classes/jars required to execute the application successfully.

     Setting classpath: Just add the dependencies in the pom.xml file will automatically add the jars in classpath.

     sample pom.xml

     <project          xmlns="http://maven.apache.org/POM/4.0.0"          xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"          xsi:schemaLocation="http://maven.apache.org/POM/4.0.0                     http://maven.apache.org/xsd/maven-4.0.0.xsd">       <modelVersion>4.0.0</modelVersion>       <groupId>com.softvision</groupId>     <artifactId>SpringMVC</artifactId>     <packaging>war</packaging>     <version>1.0-SNAPSHOT</version> lt name gt SpringMVC Json Webapp lt name...

     Check all answers on Geeksforgeeks

     2/5

   • How is CompileTime classpath different from RunTime classpath in Java?

     What is a Classpath? Classpath refers to the Path where all the classes/jars are available.

     What is Compile-time classpath? This classpath has all the classes/jars required to compile the application without any syntax error.

     Now we might think that our project compiled successfully so it will execute nicely. But this is not always true why because in some cases(explained below) to execute the project successfully you may need some other class/jars at runtime. That is why run-time classpath comes into the picture.

     What is Run-time classpath? Classpath that has all the classes/jars required to execute the application successfully.

     Setting classpath: Just add the dependencies in the pom.xml file will automatically add the jars in classpath.

     sample pom.xml

     <project          xmlns="http://maven.apache.org/POM/4.0.0"          xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"          xsi:schemaLocation="http://maven.apache.org/POM/4.0.0                     http://maven.apache.org/xsd/maven-4.0.0.xsd">       <modelVersion>4.0.0</modelVersion>       <groupId>com.softvision</groupId>     <artifactId>SpringMVC</artifactId>     <packaging>war</packaging> lt version gt 1.0 SNAPSHOT lt version gt...

     Check all answers on Geeksforgeeks

     3/5

   • How to add different programming languages to Eclipse (C++, C#, Java)

     Top Answer

     Answered Mar 25, 2013 · 5 votes

     In Eclipse, use the menu Help -> Install new software. Choose "All available sites" in the combo box, wait a moment and then you can explore some other available plugins and languages.

     Depending on your version of Eclipse, you might also have a menu item Help -> Eclipse Marketplace. That one is even more comfortable, as it allows you to easily browse all plugins listed in the Eclipse Marketplace. You can also browse the marketplace in your browser and afterwards drag and drop interesting plugins from the browser to your running eclipse (if your version of eclipse is new enough).

     Check all answers on Stack Overflow

     4/5

   • How does Kotlin code get executed in an Android application, and how is it different from Java?

     Top Answer

     Answered Nov 07, 2017 · 9 votes

     how is it different from Java code execution with Android

     It isn't. Android doesn't execute Java code or Kotlin code. Instead there is the following chain:

     • Java/Kotlin/Scala/etc. compiler takes Java/Kotlin/Scala code and emits JVM bytecode in .class files.
     • Android Gradle plugin takes JVM bytecode, converts it to Dalvik bytecode (using dx program) and packs it into .apk .
     • When the .apk file is installed on device, ART converts Dalvik bytecode it contains to machine code.
     • It's that machine code (and/or Dalvik bytecode) which is executed. ART has no idea which language source code was in at step 1 and doesn't care.

     I also want to know why we write MainActivity::class.java (class.java) to reference class file.

     You don't. You write it to reference the Class object corresponding to the MainActivity class.

     Check all answers on Stack Overflow

     5/5

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2. compscicentral.com › how-is-java-different-fromHow Is Java Different From Other Languages? - Comp Sci Central

   compscicentral.com › how-is-java-different-from

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   How Is Java Different From Other Languages? The main difference between Java and any other programming language is the unique method by which Java code is executed. Unlike compiled languages such as C++, Java is compiled into bytecode which can run on any device with the Java Virtual Machine (JVM).

   • Author: Tim Statler

3. www.geeksforgeeks.org › comparison-of-java-withComparison of Java with other programming languages

   www.geeksforgeeks.org › comparison-of-java-with

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   Feb 7, 2023 · Java was basically derived from C++. C++ is both procedural and object-oriented programming language whereas Java is a pure object-oriented language. Both the languages have different objectives which means it has many differences too. The main objective of C++ is to design a system of programming.

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