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1. Top results related to define list of string

   • List of String to List of StatefulWidget Flutter

     Top Answer

     Answered Jun 28, 2021 · 1 votes

     You cannot convert a String to a StatefulWidget.

     What you can do is use the string with NavigatorState to navigate to parts of the app.

     Global key for NavigatorState

     final GlobalKey<NavigatorState> navigatorKey = new GlobalKey<NavigatorState>();-

     main.dart

     class MyApp extends StatelessWidget { @override Widget build(BuildContext context) { return MaterialApp( title: 'Flutter Demo', debugShowCheckedModeBanner: false, theme: ThemeData( primarySwatch: Colors.blue, ), navigatorKey: navigatorKey, onGenerateRoute: (routeSettings) { switch (routeSettings.name) { //add more routes as needed case 'Home': return MaterialPageRoute(builder: (context) => Home()); default: return MaterialPageRoute(builder: (context) => Profile()); } }, home: MyHomePage(title: 'Flutter Demo Home Page'), ); }}

     Navigating to the page

     You can use this navigatorKey.currentState!.pushNamed(<Route Name>) to navigate to the page.

     Example : navigatorKey.currentState!.pushNamed('Home') This will navigate you to Home page.

     In your case, you can get the routes from an API and build a bottom Navigation bar and use the string to navigate to pages.

     Example:

     navigatorKey.currentState!.pushNamed(listStatefulWidget [index]);

     Refer:

     https://stackoverflow.com/a/53397266/9074190

     https://www.filledstacks.com/post/navigate-without-build-context-in-flutter-using-a-navigation-service/

     Check all answers on Stack Overflow

     1/5

   • List of comma separated String to Map of list using java 8

     Top Answer

     Answered Feb 10, 2018 · 4 votes

     yourList.stream() .map(x -> x.split(",", 2)) .collect(Collectors.groupingBy( x -> x[0], Collectors.mapping(x -> x[1], Collectors.toList())-));

     Check all answers on Stack Overflow

     2/5

   • Define a List of Objects in C#

     Top Answer

     Answered Dec 12, 2014 · 17 votes

     It has. The syntax would be like this:

     List<Item> items = new List<Item>(){ new Item{ Id=1, Name="Ball", Description="Hello" }, new Item{ Id=2, Name="Hat", Description="Test" }}

     Check all answers on Stack Overflow

     3/5

   • List(of String()) contains String()

     Top Answer

     Answered Aug 30, 2015 · 3 votes

     Two arrays with the same contents are still not the same array. Something = Otherthing is false. That's why Contains doesn't work.

     You could instead use SequenceEqual

     to see whether any of the arrays in listStringArrays have the same contents as Otherthing.

     If listStringArrays.Any(Function(t) t.SequenceEqual(Otherthing)) Then

     Check all answers on Stack Overflow

     4/5

   • define a List like List ?

     Top Answer

     Answered Feb 13, 2015 · 49 votes

     You could use an immutable struct

     public struct Data{ public Data(int intValue, string strValue) { IntegerData = intValue; StringData = strValue; } public int IntegerData { get; private set; } public string StringData { get; private set; }}var list = new List<Data>();

     Or a KeyValuePair<int, string>

     using Data = System.Collections.Generic.KeyValuePair<int, string>...var list = new List<Data>();list.Add(new Data(12345, "56789"));-

     Other Answers

     Answered Oct 07, 2013 · 83 votes

     Depending on your needs, you have a few options here.

     If you don't need to do key/value lookups and want to stick with a List<>, you can make use of Tuple<int, string>

     :

     List<Tuple<int, string>> mylist = new List<Tuple<int, string>>();-// add an itemmylist.Add(new Tuple<int, string>(someInt, someString));-

     If you do want key/value lookups, you could move towards a Dictionary<int, string>

     :

     Dictionary<int, string> mydict = new Dictionary<int, string>();-// add an itemmydict.Add(someInt, someString);-

     Other Answers

     Answered May 18, 2021 · 40 votes

     With the new ValueTuple

     from C# 7 (VS 2017 and above), there is a new solution:

     List<(int,string)> mylist= new List<(int,string)>();-

     Which creates a list of ValueTuple type. If you're targeting .NET Framework 4.7+ or .NET/.NET Core, it's native, otherwise you have to get the ValueTuple package from nuget.

     It's a struct opposing to Tuple, which is a class. It also has the advantage over the Tuple class that you could create a named tuple, like this:

     var mylist = new List<(int myInt, string myString)>();-

     That way you can access like mylist[0].myInt and mylist[0].myString

     Check all answers on Stack Overflow

     5/5

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2. stackoverflow.com › questions › 3139118How to initialize a list of strings (List<string>) with many ...

   stackoverflow.com › questions › 3139118

   • Cached

   List<string> optionList = new List<string> {"AdditionalCardPersonAdressType"}; optionList.Add("AutomaticRaiseCreditLimit"); optionList.Add("CardDeliveryTimeWeekDay"); In this way, if you are taking values in from IO, you can add it to a dynamically allocated list.

   Usage example

   List<string> mylist = new List<string>(new string[] { "element1", "element2", "element3" });

   See more on stackoverflow

3. www.geeksforgeeks.org › lists-of-strings-in-pythonLists Of Strings In Python - GeeksforGeeks

   www.geeksforgeeks.org › lists-of-strings-in-python

   • Cached

   Feb 6, 2024 · Below, are the methods of Lists Of Strings In Python. Using Square Brackets. Using list () Constructor. Using List Comprehension. Append Strings to an Empty List. Lists Of Strings Using Square Brackets. The most straightforward way to create a list of strings is by enclosing the strings in square brackets. Here’s an example:

4. java2blog.com › list-string-javaInitialize List of String in java - Java2Blog

   java2blog.com › list-string-java

   • Cached

   May 9, 2021 · Can you initialize List of String as below: Java. 1. 2. 3. List<String> list = new List<String>(); You can't because List is an interface and it can not be instantiated with new List(). You need to instantiate it with the class that implements the List interface. Here are the common java Collections classes which implement List interface.

5. codefather.tech › blog › list-of-strings-in-pythonList of Strings in Python: How to Use Them in Your Programs

   codefather.tech › blog › list-of-strings-in-python

   • Cached

   Nov 3, 2023 · Open the Python shell and start creating a list of lists straight away. First of all, specify the name of the variable for your list followed by the equal sign. Then on the right side of the equal sign, specify the list by doing the following: Open a square bracket to start the list. Specify the elements in the list of strings separated by commas.

6. www.freecodecamp.org › news › how-to-initialize-aHow to Initialize a Java List – List of String Initialization ...

   www.freecodecamp.org › news › how-to-initialize-a

   • Cached

   Apr 14, 2023 · This will return a List object containing the elements of the array. List<String> fruitList = Arrays.asList(fruits); We can now use the fruitList object to access the elements of the list. For example, we can iterate over the list and print each element: for (String fruit : fruitList) { System.out.println(fruit); } Output: apple banana orange

7. www.geeksforgeeks.org › create-a-list-of-stringsCreate a List of Strings in Python - GeeksforGeeks

   www.geeksforgeeks.org › create-a-list-of-strings

   • Cached

   Feb 8, 2024 · Creating a list of strings is a common task in Python programming, and there are several straightforward methods to achieve this. In this article, we will explore some simple and generally used methods to create a list of strings and print the results. Create a List of Strings in Python. Below, are the methods to Create A List Of Strings in Python.

8. pythonprinciples.com › blog › lists-of-strings-in-pythonLists Of Strings In Python – Python Principles

   pythonprinciples.com › blog › lists-of-strings-in-python

   • Cached

   Create list of strings. To create a list of strings, first use square brackets [ and ] to create a list. Then place the list items inside the brackets separated by commas. Remember that strings must be surrounded by quotes. Also remember to use = to store the list in a variable. So we get something like this: