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1. Top results related to python generate list of random numbers

   • Python - Generate a list of 40 random numbers summing to 1, with min and max weight

     Top Answer

     Answered Dec 29, 2021 · 1 votes

     Perhaps using np.random.normal would give better results. You could scale down the distribution to the 0.005-0.045 range using the proportion of 80% that is variable (above 0.005). Because normal distributions can still have outliers, it will be necessary to "retry" the calculation if the values go out of bounds (but that shouldn't happen too frequently unless you give a large standard deviation):

     import numpy as np

     def randStock(count=40,minR=0.005,maxR=0.045,sd=3): iterations = 0 while True: iterations += 1 r = np.random.normal(1,sd,count) #normal distribution r -= min(r) # offset to zero r /= max(r) # scale to 0..1 r = minR + r/sum(r)*(maxR-minR)/(maxR+minR) # scale to range if min(r)>=minR and max(r)<=maxR: return r, iterations-

     Output:

     for _ in range(10): s,i = randStock() print(*map("{:6.4f}".format,(sum(s),min(s),max(s))),i,"iterations")-[sum] [min] [max] [mean] 1.0000 0.0050 0.0404 0.0250 1 iterations1.0000 0.0050 0.0409 0.0250 2 iterations1.0000 0.0050 0.0395 0.0250 1 iterations1.0000 0.0050 0.0411 0.0250 4 iterations1.0000 0.0050 0.0410 0.0250 2 iterations1.0000 0.0050 0.0428 0.0250 1 iterations1.0000 0.0050 0.0433 0.0250 1 iterations1.0000 0.0050 0.0424 0.0250 1 iterations1.0000 0.0050 0.0371 0.0250 1 iterations1.0000 0.0050 0.0446 0.0250 1 iterations-

     Note that this could be improved to randomize the lower bound a bit more and you can chose a different standard deviations

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     1/5

   • Generate a list of 6 random numbers between 1 and 6 in python

     Top Answer

     Answered Oct 07, 2018 · 13 votes

     Use a list comprehension:

     import random-def startTheGame():- mylist=[random.randint(1, 6) for _ in range(6)] return mylist

     List comprehensions are among the most powerful tools offered by Python. They are considered very pythonic and they make code very expressive.

     Consider the following code:

     counter = 0myList = []while (counter) < 6: randomNumber = random.randint(1, 6)-myList.append(randomNumber)counter = counter + 1if (counter)>=6: passelse: return

     We will refactor this code in several steps to better illustrate what list comprehensions do. First thing that we are going to refactor is the while loop with an initialization and an abort-criterion. This can be done much more concise with a for in expression:

     myList = []for counter in range(6): randomNumber = random.randint(1, 6)myList.append(randomNumber)-

     And now the step to make this piece of code into a list comprehension: Move the for loop inside mylist. This eliminates the appending step and the assignment:

     [random.randint(1, 6) for _ in range(6)]-

     The _ is a variable name just like any other, but it is convention in python to us e _ for variables that are not used. Think of it as a temp variable.

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     2/5

   • Generate list of random names - Python

     Top Answer

     Answered Dec 01, 2016 · 5 votes

     you're just duplicating your string here. Random occurs only once.

     Do it in a generator comprehension instead, and join the results with space:

     import random-first_names=('John','Andy','Joe')last_names=('Johnson','Smith','Williams')group=" ".join(random.choice(first_names)+" "+random.choice(last_names) for _ in range(3))print(group)

     outputs:

     Joe Williams Joe Johnson Joe Smith-

     Other Answers

     Answered Dec 01, 2016 · 4 votes

     This is because you generated one name and then replicated it three times.

     If you want three different names, then loop through your choice routine three times:

     group = []for i in range(3): full_name=random.choice(first_names)+" "+random.choice(last_names) group.append(full_name) #assuming he wants at least some kind of seperator between the names. group_string = ", ".join(group)

     BTW, do you really want group to be all the names just concatenated?

     Other Answers

     Answered Dec 01, 2016 · 1 votes

     Since the output is on one line with spaces separating each name, you can simplify the code and store every name in one list, albeit you append names in the "first name" "last name" pattern. From there you can print 6 names at the end all seperated by a space, giving you three full names. In all, the 'random.choice()' function will need to be called 6 times.

     import random-first_names=('John','Andy','Joe')last_names=('Johnson','Smith','Williams')names = []for i in range(3): names.append(random.choice(first_name) names.append(random.choice(last_name)print ' '.join(names)

     output

     Andy Smith Andy Williams John Johnson-

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     3/5

   • Generate random numbers from a list of numbers

     Top Answer

     Answered Jan 29, 2020 · 1 votes

     You can simply use np.random.choice:

     import numpy as np data=[15,30,45]N = 50new_list = np.random.choice(data,N)-

     Edit: Using random.sample() won't work as the sampling is done without replacement, therefore samples can't exceed length of the original data.

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     4/5

   • Generate random list of timestamps in python

     Top Answer

     Answered Oct 03, 2023 · 12 votes

     The whole point of the datetime library: datetime, timedelta, etc. objects act as much like numbers as possible, so you can just do arithmetic on them.

     So, to generate a uniform distribution over a day, just take a uniform distribution from 0.0 to 1.0, and multiply it by a day:1

     td = random.random() * datetime.timedelta(days=1)-

     To generate a uniform random time on some particular day, just add that to midnight on that day:

     dt = datetime.datetime(2018, 5, 1) + random.random() * datetime.timedelta(days=1)-

     To generate a random timestamp between two timestamps:

     dt = random.random() * (end - start) + start-

     And if you want 10 of those:

     [random.random() * (end - start) + start for _ in range(10)]-

     That's all there is to it. Stay away from all those other time formats from the time module; they're only needed if you need compatibility with stuff like C libraries and filesystem data. Just use datetime in the first place:

     def randomtimes(start, end, n): frmt = '%d-%m-%Y %H:%M:%S' stime = datetime.datetime.strptime(start, frmt) etime = datetime.datetime.strptime(end, frmt) td = etime - stime return [random.random() * td + stime for _ in range(n)]

     1. However, keep in mind that if you're dealing with local rather than UTC times, some days are actually 23 or 25 hours long, because of Daylight Saving Time. A timedelta

     doesn't understand that.

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     5/5

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2. www.geeksforgeeks.org › generating-random-numberGenerating random number list in Python - GeeksforGeeks

   www.geeksforgeeks.org › generating-random-number

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   Aug 18, 2022 · Method 1: Using the random.randint () By using random.randint () we can add random numbers into a list. Python3. import random. rand_list=[] n=10. for i in range(n): rand_list.append(random.randint(3,9)) print(rand_list) Output. [9, 3, 3, 6, 8, 5, 4, 6, 3, 7] Method 2: Using random.sample ()

3. stackoverflow.com › questions › 16655089Python: Random numbers into a list - Stack Overflow

   stackoverflow.com › questions › 16655089

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   You could use random.sample to generate the list with one call: import random my_randoms = random.sample(range(100), 10) That generates numbers in the (inclusive) range from 0 to 99. If you want 1 to 100, you could use this (thanks to @martineau for pointing out my convoluted solution): my_randoms = random.sample(range(1, 101), 10)

   Code sample

   import random

   my_randoms = [random.randrange(1, 101, 1) for _ in range(10)]

   See more on stackoverflow

4. People also ask

   How to generate random numbers in Python?

   • Let’s discuss certain ways in which this can be done. Python Random module is an in-built module of Python which is used to generate random numbers. This module can be used to perform random actions such as generating random numbers, printing random a value for a list or string, etc. By using random.randint () we can add random numbers into a list.

   Generating random number list in Python - GeeksforGeeks

   www.geeksforgeeks.org/generating-random-number-list-in-python/

   See all results for this question

   What is a random module in Python?

   • Python Random module is an in-built module of Python which is used to generate random numbers. This module can be used to perform random actions such as generating random numbers, printing random a value for a list or string, etc. By using random.randint () we can add random numbers into a list. Output

   Generating random number list in Python - GeeksforGeeks

   www.geeksforgeeks.org/generating-random-number-list-in-python/

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   Is Python random?

   • First, a prominent disclaimer is necessary. Most random data generated with Python is not fully random in the scientific sense of the word. Rather, it is pseudorandom: generated with a pseudorandom number generator (PRNG), which is essentially any algorithm for generating seemingly random but still reproducible data.

   Generating Random Data in Python (Guide) – Real Python

   realpython.com/python-random/

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   How to generate a random float in Python?

   • Almost all module functions depend on the basic function random(), which generates a random float uniformly in the half-open range 0.0 <= X < 1.0 . Python uses the Mersenne Twister as the core generator. It produces 53-bit precision floats and has a period of 2**19937-1. The underlying implementation in C is both fast and threadsafe.

   random — Generate pseudo-random numbers — Python 3.12

   docs.python.org/3/library/random.html

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5. codefather.tech › blog › create-list-of-randomHow to Create a List of Random Numbers in Python

   codefather.tech › blog › create-list-of-random

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   Nov 26, 2023 · You can generate a list of random numbers by simply putting together a function provided by Python’s random module with a while loop. The following code uses the randint() function of Python’s random built-in module and a while loop to generate a list of random integers: >>> random_integers = [] >>> while len(random_integers) < 10:

6. docs.python.org › 3 › libraryrandom — Generate pseudo-random numbers — Python 3.12.3 ...

   docs.python.org › 3 › library

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   1 day ago · Source code: Lib/random.py. This module implements pseudo-random number generators for various distributions. For integers, there is uniform selection from a range. For sequences, there is uniform selection of a random element, a function to generate a random permutation of a list in-place, and a function for random sampling without replacement.

7. realpython.com › python-randomGenerating Random Data in Python (Guide) – Real Python

   realpython.com › python-random

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   If you wanted to generate a sequence of random numbers, one way to achieve that would be with a Python list comprehension: Python >>> [ random . random () for _ in range ( 5 )] [0.021655420657909374, 0.4031628347066195, 0.6609991871223335, 0.5854998250783767, 0.42886606317322706]

8. www.tutorialspoint.com › generating-random-numberGenerating random number list in Python

   www.tutorialspoint.com › generating-random-number

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   Aug 22, 2023 · We first create an empty list and then append the random numbers generated to the empty list one by one. Example. import random. randomlist = [] for i in range(0,5): . n = random.randint(1,30) . randomlist.append(n) print(randomlist) Output. Running the above code gives us the following result −. [10, 5, 21, 1, 17] Using random.sample ()

9. pynative.com › python › randomPython Random Module: Generate Random Numbers and Data - PYnative

   pynative.com › python › random

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   Jun 16, 2021 · import random number_list = [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] print("First Sample is ", random.sample(number_list, k=5)) # Output [3, 27, 21, 24, 18] # Get current state and store state = random.getstate() # set current state random.setstate(state) # Now it will print the same second sample list print("Second Sample is ", random.sample ...