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  1. The first series of three episodes aired in 2010, while series two aired in 2012, and a third series aired in the first quarter of 2014. A single episode aired in 2016, as a Victorian-era special, followed by a fourth series in 2017. As of 15 January 2017, 13 episodes of Sherlock have aired, including one special, concluding the fourth series.

  2. Sherlock is a modernized crime drama series based on Conan Doyle's characters, starring Benedict Cumberbatch and Martin Freeman. IMDb provides information on 15 episodes, 9 seasons, awards, trivia, and more.

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  3. Created by Steven Moffat and Mark Gatiss, the show stars Benedict Cumberbatch as Sherlock Holmes and Martin Freeman as Doctor John Watson. Thirteen episodes have been produced, with four three-part series airing from 2010 to 2017 and a special episode that aired on 1 January 2016.

    • 25 July 2010 –, 15 January 2017
  4. Mysterious symbols and murders are showing up all over London, leading Sherlock and John to a secret Chinese crime syndicate called Black Lotus.

    • Series 4. View episodes. Sherlock and John Watson return in a contemporary take on Conan Doyle's iconic adventures. The Final Problem. 3/3 Alone and defenceless, Sherlock and Dr Watson face their greatest ever challenge.
    • The Abominable Bride. Sherlock and John investigate a ghostly bride who appears to have committed murder.
    • Series 3. View episodes. Sherlock returns - but will things ever be the same again? Series 3 homepage.
    • Series 2. View episodes. Sherlock and John Watson return in a contemporary take on Conan Doyle's iconic adventures. Series 2 homepage.
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  6. Sherlock Season 4 features three episodes that promise laughter, tears, shocks, surprises and extraordinary adventures. Sherlock Holmes (Benedict Cumberbatch) is back once more on British...

  7. www.pbs.org › show › sherlockSherlock | PBS

    The world’s only consulting detective, Sherlock Holmes (Benedict Cumberbatch), teams up with his long-suffering, faithful friend, Dr. John Watson (Martin Freeman), to solve a dizzying array of ...

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